Suppose a family has three children of different ages. We assume that all combinations of boys and girls are equally likely. (a)
1 answer:
Answer:
a) There are 8 possible combinations and each probability is 1/8.
b) The probability that it is a boy given that there are two girls is 3/8
Step-by-step explanation:
a) The sample space is given by:
BBB (3 boys)
BBG (Boy, boy, girl)
BGB (Boy, girl, boy)
BGG (Boy, girl, girl)
GBB (girl, boy, boy)
GBG (girl, boy, girl)
GGB (girl, girl, boy)
GGG (3 girls)
The probability of each combination is the same:
P(BBB)=P(B∩B∩B)=
2) There are three possible combinations in which there are 2 girls and 1 boy:
BGG, GBG, GGB
So the probability is given by:
P(BGG ∪ GBG ∪ GGB)=
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