PLEASE HELP (unknown answers will be deleted)

Mathematics

1 answer:

Shtirlitz [24]3 years ago

8 0

Answer:

where's the assignment

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We wish to construct a 90% confidence interval on the mean of a population known to be normally distributed based on a sample of

sergiy2304 [10]

Answer:

Margin of error = 0.773

Step-by-step explanation:

We are given the following information in the question.

Sample size, n = 20

Sample mean = 8

Sample standard deviation = 2

90% Confidence interval

$\bar{x} \pm t_{critical}\displaystyle\frac{s}{\sqrt{n}}$

Putting the values, we get,

$t_{critical}\text{ at degree of freedom 19 and}~\alpha_{0.10} = \pm 1.729$

Margin of error:

$t_{critical}\displaystyle\frac{s}{\sqrt{n}}$

Putting the values, we get,

$1.729(\frac{2}{\sqrt{20}} ) = 0.773$

7 0

3 years ago

F two angles have the same vertex, then they are adjacent.

arlik [135]

Are you asking if it's true or false?
Because it's false, they are not necessarily adjacent.

4 0

2 years ago

The area of triangle ABC is _____.

Marizza181 [45]

I FOUND YOUR COMPLETE QUESTION IN OTHER SOURCES.
SEE ATTACHED IMAGE.
Using Heron's Formula we can find the area of the triangle.
A = root (s (s-a) * (s-b) * (s-c))
s = (a + b + c) / 2
Where,
s: semi-perimeter
a, b, c: sides of the triangle
Substituting values:
s = (15 + 16 + 20) / 2
s = 25.5
s = 26
The area will be:
A = root (26 * (26-15) * (26-16) * (26-20))
A = 130.9961832
A = 130 u ^ 2
Answer:
The area of triangle ABC is:
C.
130 u ^ 2