Answer:
-2
Step-by-step explanation:
intercept at (0, -2)
Answer:
1767 cm³
Step-by-step explanation:
We can use volume V = 4/3 π r³
We have diameter of 15 cm. To get radius, we need to divide diameter by 2.
r = 7.5 cm
So now plug in r = 7.5 then calculate V:
V = 4/3 π ( 7.5 )³
V = 4/3 π * 421.875 ≈ 1767.145 ≈ 1767
Hope this helps.
9514 1404 393
Answer:
- (c1, c2, c3) = (-2t, 4t, t) . . . . for any value of t
- NOT linearly independent
Step-by-step explanation:
We want ...
c1·f1(x) +c2·f2(x) +c3·f3(x) = g(x) ≡ 0
Substituting for the fn function values, we have ...
c1·x +c2·x² +c3·(2x -4x²) ≡ 0
This resolves to two equations:
x(c1 +2c3) = 0
x²(c2 -4c3) = 0
These have an infinite set of solutions:
c1 = -2c3
c2 = 4c3
Then for any parameter t, including the "trivial" t=0, ...
(c1, c2, c3) = (-2t, 4t, t)
__
f1, f2, f3 are NOT linearly independent. (If they were, there would be only one solution making g(x) ≡ 0.)
Answer:
Step-by-step explanation:
We know that:
In a deck of 52 cards there are 4 aces.
Therefore the probability of obtaining an ace is:
P (x) = 4/52
The probability of not getting an ace is:
P ('x) = 1-4 / 52
P ('x) = 48/52
In this problem the number of aces obtained when extracting cards from the deck is a discrete random variable.
For a discrete random variable V, the expected value is defined as:
Where V is the value that the random variable can take and P (V) is the probability that it takes that value.
We have the following equation for the expected value:
In this problem the variable V can take the value V = 9 if an ace of the deck is obtained, with probability of 4/52, and can take the value V = -1 if an ace of the deck is not obtained, with a probability of 48 / 52
Therefore, expected value for V, the number of points obtained in the game is:
So:
Answer:
20 units
Step-by-step explanation:
Since the triangle is equilateral then all 3 sides are equal in length.
Equate any 2 sides and solve for x
4x = 3x + 5 ( subtract 3x from both sides )
x = 5
hence
4x = 4 × 5 = 20
3x + 5 = (3 × 5) + 5 = 15 + 5 = 20
7x - 15 = (7 × 5) - 15 = 35 - 15 = 20
The lengths of the sides are 20 units