Answer:

Step-by-step explanation:
We are given that

Differentiate w.r.t x

By using formula







Hence, the derivative of function

Answer:
-4.3
Step-by-step explanation:
5.4 +(-9.7)
= 5.4-9.7
=-4.3
Answer:
Step-by-step explanation:
The total cost of the bench would be $72 after the markdown being 10% from the orginal proce which was $80.
Please note that your x^3/4 is ambiguous. Did you mean (x^3) divided by 4
or did you mean x to the power (3/4)? I will assume you meant the first, not the second. Please use the "^" symbol to denote exponentiation.
If we have a function f(x) and its derivative f'(x), and a particular x value (c) at which to begin, then the linearization of the function f(x) is
f(x) approx. equal to [f '(c)]x + f(c)].
Here a = c = 81.
Thus, the linearization of the given function at a = c = 81 is
f(x) (approx. equal to) 3(81^2)/4 + [81^3]/4
Note that f '(c) is the slope of the line and is equal to (3/4)(81^2), and f(c) is the function value at x=c, or (81^3)/4.
What is the linearization of f(x) = (x^3)/4, if c = a = 81?
It will be f(x) (approx. equal to)
Descriptions 1, 2, 3, and 5 are accurate, though 5 is ambiguous.
_____
Description 4 goes with (7x)² = 49x², not 7x².
Description 6 goes with 5·8 + x² + (2x + 8) = x² +2x +48, not 40x² +100x +40.
The description for 5 is accurate, but could also be applied to y² + 3(y - 4), which is why it can be considered to be ambiguous. There are a number of ways to resolve the ambiguity, but they were not used here.