What is the product of 7-8i

Jane has already run 6 miles this month. She plans to run an additional 2.5 miles per day.

mixas84 [53]

Answer: It will take Jane 14 days to run 41 miles

Explanation: The problem asks how long it will take Jane to run 41 miles, we know Jane has ran 6 miles already so:
41-6= 35
Jane is running 2.5 miles a day therefore:
35 ÷ 2.5 = 14

7 0

2 years ago

What is the approximate measure of angle T in the triangle below 79° 84° 96° 101°

Anestetic [448]

The approximate measure of angle T in the given diagram is 79°. The correct option is the first option 79°

<h3>Law of Cosines</h3>

From the question, we are to determine the approximate measure of angle T

From the law of cosines, we can write that

cosT = (s² + u² - t²)/2su

From the diagram,

s = 3.9 cm

u = 2.7 cm

t = 4.3 cm

Thus,

cosT = (3.9² + 2.7² - 4.3²)/2(3.9)(2.7)

cosT = (15.21 + 7.29 - 18.49)/21.06

cosT = 4.01/21.06

cosT = 0.1904

T = cos⁻¹(0.1904)

T = 79.02°

T ≈ 79°

Hence, the approximate measure of angle T in the given diagram is 79°. The correct option is the first option 79°

Learn more on Law of Cosines here: brainly.com/question/28081595

#SPJ1

4 0

1 year ago

10. In a survey of 212 people at the local track and field championship, 72% favored the home team

igomit [66]

Answer:

a. The margin of error for the survey is of 0.0308 = 3.08%.

b. The 95% confidence interval that is likely to contain the exact percent of all people who favor the home team winning is (65.96%, 78.04%).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the z-score that has a p-value of $1 - \frac{\alpha}{2}$ .

The margin of error of the survey is:

$M = \sqrt{\frac{\pi(1-\pi)}{n}}$

The confidence interval can be written as:

$\pi \pm zM$

In a survey of 212 people at the local track and field championship, 72% favored the home team winning.

This means that $n = 212, \pi = 0.72$

a. Find the margin of error for the survey.

$M = \sqrt{\frac{0.72*0.28}{212}} = 0.0308$

The margin of error for the survey is of 0.0308 = 3.08%.

b. Give the 95% confidence interval that is likely to contain the exact percent of all people who favor the home team winning.

95% confidence level

So $\alpha = 0.05$ , z is the value of Z that has a p-value of $1 - \frac{0.05}{2} = 0.975$ , so $Z = 1.96$ .

Lower bound:

$\pi - zM = 0.72 - 1.96*0.0308 = 0.6596$

Upper bound:

$\pi + zM = 0.72 + 1.96*0.0308 = 0.7804$

As percent:

0.6596*100% = 65.96%

0.7804*100% = 78.04%.

The 95% confidence interval that is likely to contain the exact percent of all people who favor the home team winning is (65.96%, 78.04%).

7 0

3 years ago

The ratio of irises to The ratio of irises to roses in Nikki's garden is 2:5. She currently has 25 roses. She is planning to add

denpristay [2]

If the proportion of iris to roses in Nikki's garden is 2: 5, it means that for 25 roses: (2/5) = (10/25). Therefore to maintain the proportion by adding 20 roses: (2/5) = (18/45). The number of irises after the addition of roses will be 10 + 18 = 28 irises.

5 0

3 years ago

The accountant charged $35 for the first hour of work and $23 for each hour after that.He earned a total of$127 how many hours d

dexar [7]

Answer:

He worked a total of 5 hours.

Step-by-step explanation:

The first hour the man makes $35 dollars for the first hour then for the other hours he earns $23 dollars, right? So we start off with 35.

35 = one hour.

35 + 23 = 2 hours . = 58.

35 + 23 + 23 = 3 hours. = 81.

35 + 23 + 23 + 23 = 4 hours. = 104.

35 + 23 + 23 + 23 + 23 = 5 hours. = 127.

We were looking for if the man earned $127 dollars how many hours would be be working.

He'd be working 5 hours.

Hope this helps (:

5 0

3 years ago