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3 years ago

6

Mai runs each lap in 8 minutes. She will run more than 88 minutes today. What are the possible numbers of laps she will run toda

y? Use n for the number of laps she will run today.

1 answer:

Readme [11.4K]3 years ago

4 0

Answer: 88<8n

Step-by-step explanation:

Because 88 is the least amount of time, it goes on one side of the inequity and the 8n goes on the other

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Show why the limit as x approaches 0 (csc(x)-cot(x)) involves an indeterminate form, and then prove that the limit equals 0.

Nadusha1986 [10]

Answer with Step-by-step explanation:

We are given that $\lim_{x\rightarrow 0 }(csc(x)-cot(x))$

We have to prove that why the limit x approaches 0(csc(x)-cot(x)) involves an indeterminate form and prove that the limit equals to 0.

$\lim_{x\rightarrow 0 }(\frac{1}{sinx}-\frac{cosx}{sinx})$

Because $csc(x)=\frac{1}{sinx}$ and $cot(x)=\frac{cosx}{sinx}$

$\lim_{x\rightarrow 0 }(\frac{1-cosx}{sinx})$

$\frac{1-cos0}{sin0}$

We know that cos 0=1 and sin 0=0

Substitute the values then we get

$\frac{1-1}{0}=\frac{0}{0}$

We know that $\frac{0}{0}$ is indeterminate form

Hence, the limit x approaches 0(csc(x)-cot(x)) involves an indeterminate form.

L'hospital rule:Apply this rule and differentiate numerator and denominator separately when after applying $\lim_{x\rightarrow a }$ we get indeterminate form $\frac{0}{0}$

Now,using L' hospital rule

$\lim_{x\rightarrow 0 }\frac{0+sinx}{cosx}$

because $\frac{dsinx}{dx}=cosx,\frac{dcosx}{dx}=-sinx}$

Now, we get

$\lim_{x\rightarrow 0 }\frac{sinx}{cos x}$

$\frac{sin0}{cos0}$

$\frac{0}{1}=0$

Hence, $\lim_{x\rightarrow 0 }(csc(x)-cot(x))=0$

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Y = 4X-3<br> 4.88-1:2y = 3.6

Rzqust [24]

Answer:

google it , it'll help you

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Aleks [24]

2/4= 10/20
1 4/10=14/10 14/10=28/20

10/20×28/20=7/10

I hope this helped!!!:)

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4 years ago