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kow [346]
3 years ago
5

Dave is meeting his friends at 7:30 P.M. The average speed of the bus is 28 km/h, and he needs to travel 20 km. When should he c

atch his bus? Describe your strategy and whether it was appropriate.
Mathematics
1 answer:
Gwar [14]3 years ago
7 0
20 / 28 = 0,7
0,7 * 60 = 42 

Dave should catch the bus at 6:48 PM.
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2 years ago
According to an​ article, 47​% of adults have experienced a breakup at least once during the last 10 years. Of 9 randomly select
In-s [12.5K]

Answer:

a) P(X=5)=(9C5)(0.47)^5 (1-0.47)^{9-5}=0.228

b) P(X=0)=(9C0)(0.47)^0 (1-0.47)^{9-0}=0.0033

And replacing we got:

P(X \geq 1)= 1-P(X

c) P(X=4)=(9C4)(0.47)^4 (1-0.47)^{9-4}=0.257

P(X=5)=(9C5)(0.47)^5 (1-0.47)^{9-5}=0.228

P(X=6)=(9C6)(0.47)^6 (1-0.47)^{9-6}=0.135

And adding we got:

P(4 \leq X \leq 6)= 0.257+0.228+0.135=0.620

Step-by-step explanation:

Previous concepts

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".

Solution to the problem

Let X the random variable of interest, on this case we now that:

X \sim Binom(n=9, p=0.47)

The probability mass function for the Binomial distribution is given as:

P(X)=(nCx)(p)^x (1-p)^{n-x}

Where (nCx) means combinatory and it's given by this formula:

nCx=\frac{n!}{(n-x)! x!}

Assuming the following questions:

a. exactly five

For this case we can use the probability mass function and we got:

P(X=5)=(9C5)(0.47)^5 (1-0.47)^{9-5}=0.228

b. at least one

For this case we want this probability:

P(X \geq 1)

And we can use the complement rule and we got:

P(X \geq 1)= 1-P(X

P(X=0)=(9C0)(0.47)^0 (1-0.47)^{9-0}=0.0033

And replacing we got:

P(X \geq 1)= 1-P(X

c. between four and six, inclusive.

For this case we want this probability:

P(4 \leq X \leq 6)

P(X=4)=(9C4)(0.47)^4 (1-0.47)^{9-4}=0.257

P(X=5)=(9C5)(0.47)^5 (1-0.47)^{9-5}=0.228

P(X=6)=(9C6)(0.47)^6 (1-0.47)^{9-6}=0.135

And adding we got:

P(4 \leq X \leq 6)= 0.257+0.228+0.135=0.620

6 0
3 years ago
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