Question

Solve 0 = 4x2+12x+9.

Answer 1

Answer:

C

Step-by-step explanation:

Just did the question

Answer 2

Answer:

The correct  substitution of a, b, and c in the quadratic formula is given by

$x=\frac{-12\pm\sqrt{(12)^2-4(4)(9)}}{2(4)}$

$x = - \frac{ 3}{2} \: and \: x = -\frac{ 3}{2}$

The solutions of the given quadratic equation are real and equal.

Step-by-step explanation:

The given quadratic equation is

$4x^2+12x+9 = 0$

The coefficients a, b and c are as follow:

$a = 4 \\\\b = 12\\\\c = 9$

The quadratic formula is given by

$x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$

The correct  substitution of a, b, and c in the quadratic formula is given by

$x=\frac{-12\pm\sqrt{(12)^2-4(4)(9)}}{2(4)}$

Bonus:

The solution of this quadratic equation is given by

$x=\frac{-12\pm\sqrt{(144 - 144)}}{8} \\\\x=\frac{-12\pm\sqrt{0}}{8} \\\\x=\frac{-12\pm 0}{8} \\\\x=\frac{-12 + 0}{8} \: and \: x=\frac{-12 - 0}{8}\\\\x= -\frac{ 3}{2} \: and \: x = -\frac{ 3}{2}$

Therefore, the solutions of the given quadratic equation are real and equal.