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Mathematics

1 answer:

Gala2k [10]3 years ago

6 0

119.25 is the right answer for this question

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A students work to simplify a radical is shown below. Select the statemmebt which best applies to rhe sample mathematical work

Citrus2011 [14]

Answer:

D. The work shown above is correct, and $y^5.\sqrt[4]{y^3}$ may not be simplified further.

Step-by-step explanation:

$\sqrt[4]{y^{23} } = \sqrt[4]{y^4 . y^4 . y^4.y^4.y^3}$

$\sqrt[4]{y^4. y^4.y^4. y^4.y^3} = y^5 . \sqrt[4]{y^3}$

When we simplify, we get

$\sqrt[4]{y^{23} } = y^5.\sqrt[4]{y^3}$

The answer: D. The work shown above is correct, and $y^5. \sqrt[4]{y^3}$ may not be simplified further.

Thank you.

4 0

3 years ago

Find the TWO integers whos product is -12 and whose sum is 1<br>

ahrayia [7]

Answer:

$\rm Numbers = 4 \ and \ -3.$

Step-by-step explanation:

Given :-

The sum of two numbers is 1 .

The product of the nos . is 12 .

And we need to find out the numbers. So let us take ,

First number be x

Second number be 1-x .

According to first condition :-

$\rm\implies 1st \ number * 2nd \ number= -12\\\\\rm\implies x(1-x)=-12\\\\\rm\implies x - x^2=-12\\\\\rm\implies x^2-x-12=0\\\\\rm\implies x^2-4x+3x-12=0\\\\\rm\implies x(x-4)+3(x-4)=0\\\\\rm\implies (x-4)(x+3)=0\\\\\rm\implies\boxed{\red{\rm x = 4 , -3 }}$