Let x and y be the 2 parts of 15 ==> x + y=15 (given)
Reciprocal of x and y ==> 1/x +1/y ==> 1/x + 1/y = 3/10 (given)
Let's solve 1/x + 1/y = 3/10 . Common denominator = 10.x.y (reduce to same denominator)
==> (10y+10x)/10xy = 3xy/10xy ==> 10x+10y =3xy
But x+y = 15 , then 10x+10y =150 ==> 150=3xy and xy = 50
Now we have the sum S of the 2 parts that is S = 15 and
their Product = xy =50
Let's use the quadratic equation for S and P==> X² -SX +P =0
Or X² - 15X + 50=0, Solve for X & you will find:
The 1st part of 15 is 10 & the 2nd part is 5
Note: Let us consider, we need to find the
and
.
Given:
In the given figure, BD is the angle bisector of ABC.
To find:
The
and
.
Solution:
BD is the angle bisector of ABC. So,




Divide both sides by 2.


Now,



And,





Therefore,
and
.
Answer:
1500 pot holders
Step-by-step explanation:
32×48=1536 so it's about 1500 pot holders because 1536 it's closet to 1500
Answer:
x = -3 or x = 3
Step-by-step explanation:
Subtract 9 from both sides.
x^2 - 9 = 0
Factor the left side. There is no common factor of the terms. It is a binomial which is the difference of two squares, so it factors into the product of a sum and a difference.
(x + 3)(x - 3) = 0
Set each factor equal to zero.
x + 3 = 0 or x - 3 = 0
Solve each equation.
x = -3 or x = 3
Answer:
12a+2b
Step-by-step explanation:
1. Expand by distributing terms.
20a-8b-2(4a-5b)20a−8b−2(4a−5b)
2. Expand by distributing terms.
20a-8b-(8a-10b)20a−8b−(8a−10b)
3. Remove parentheses.
20a-8b-8a+10b20a−8b−8a+10b
4.Collect like terms.
(20a-8a)+(-8b+10b)(20a−8a)+(−8b+10b)
5. Simplify.
12a+2b12a+2b
6.Answer
12a+2b