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harina [27]
3 years ago
5

Suppose you choose a marble from a bag containing 3 red marbles. 3 white marbles, and 5 blue marbles. You return the first marbl

e to the bag and then choose
again. Find
red then blue).
11​
Mathematics
1 answer:
Flauer [41]3 years ago
5 0

Answer:

15/121.

Step-by-step explanation:

Probability of picking a red = number of reds in the bag / total number of marbles in the bag

= 3 / (3 + 3 + 5)

= 3/11.

Probability of picking a blue = 5/11.

These 2 events are independent so we multiply probabilities, therefore the

Probability of (a red then a blue) = 3/11 * 5 /11

= 15/121.

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Which of the following is true of the constructions of an equilateral triangle, a square, and a regular hexagon when they are in
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<span>a regular hexagon inscribed in a circle </span>
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When a group of 40 friends goes to the movies at a multiplex, 1/5 of the group decides to watch a science friction movie.How man
Sladkaya [172]

Answer: 8 members of the science group decided to watch the science fiction movie

Step-by-step explanation:

When a group of 40 friends goes to the movies at a multiplex, 1/5 of the group decides to watch a science friction movie. This means that the total sum of the members of the group that decided to watch the science fiction movie and the members that did not watch the science fiction movie is 40.

If 1/5 of the group decides to watch a science friction movie, that means that 1/5 of 40 watched the science fiction movie. It becomes

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8 members of the science group decided to watch the science fiction movie.

7 0
3 years ago
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professor190 [17]
Area of a trapezoid
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a = 12.9, b = 8.6, h = 6.4

A = 1/2(12.9 + 8.6)(6.4) = 68.8 cm²
4 0
3 years ago
The variables x and y have a quadratic relationship. Tripling the value of x causes the value of y to increase by a factor of ni
Lady bird [3.3K]

Answer:

<em>The value of y when x has a value of 9 is 18</em>

Step-by-step explanation:

<u>Functions</u>

The variables x and y are said to have a quadratic relationship. That information is not enough to set up a general equation for both variables.

Furthermore, we know that tripling the value of x causes the value of y to be multiplied by 9. That leads us to establish a proportional equation between them, as follows:

y=kx^2

Where k is an unknown constant.

Let's use the given point (3,2) to find the value of k:

2=k(3)^2

2=9k

Solving for k:

\displaystyle k=\frac{2}{9}

The equation is now:

\displaystyle y=\frac{2}{9}x^2

Now find y when x=9:

\displaystyle y=\frac{2}{9}(9)^2

\displaystyle y=\frac{2}{9}\cdot 81=18

The value of y when x has a value of 9 is 18

3 0
3 years ago
paula and ricardo are serving cupcakes at a school party. if they arrange the cupcakes in groups of 2,3,4,5 or 6, they always ha
slega [8]
Find the smallest number that is divisible by 2, 3, 4, 5, 6 and add 1.
We need the least common multiple of 2, 3, 4, 5, 6.

2 = 2
3 = 3
4 = 2^2
5 = 5
6 = 2 * 3

LCM = product of common and not common prime factors with larger exponent.

LCM = 2^2 * 3 * 5 = 4 * 3 * 5 = 60

To always have a remainder of 1, you need of add 1 to 60.

The number is 61.

Check:
61/2 = 30 remainder 1
61/3 = 20 remainder 1
61/4 = 15 remainder 1
61/5 = 12 remainder 1
61/6 = 10 remainder 1
4 0
3 years ago
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