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ololo11 [35]
3 years ago
10

93000000 in standard form

Mathematics
1 answer:
noname [10]3 years ago
3 0
It’s already in standard form: 93,000,000

If we would put it in scientific notation though, it would be: 9.3 x10 ^7 (to the power of 7)
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Which rational expression has a value of 0 when x=-2
Ad libitum [116K]
Im sorry. I need the options to answer this...
But if you want to answer this your self just take all your options and replace x with -2 and use PEMDAS to find if it equals 0 or not.
3 0
3 years ago
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Help me with this please
Mashcka [7]
Answer-146

Add all the numbers and because 360 is how much a circle is equal to subtract 360 by 68 which is what you will get if you add the numbers up and after you will get 246 so just divide 246 by 2 and u get 146
7 0
3 years ago
I need help with this problem, if anyone could help ASAP, that would be much appreciated. In the figure below, mROP = 125° Find
VARVARA [1.3K]

Answer:

mRP = 125°

mQS = 125°

mPQR = 235°

mRPQ = 305°

Step-by-step explanation:

Given that

  • mROP = 125°
  • ∠ROP is a central angle

Then:

  • measure of arc RP, mRP = mROP = 125°

Given that

  • ∠QOS and ∠ROP are vertical angles

Then:

  • mQOS = mROP = 125°
  • measure of arc QS, mQS = mROP = 125°

Given that

  • ∠QOR and ∠SOP are vertical angles

Then:

  • mQOR = mSOP

Given that

  • The addition of all central angles of a circle is 360°

Then:

mQOS + mROP + mQOR + mSOP = 360°

250° + 2mQOR = 360°

mQOR = (360°- 250°)/2

mQOR = mSOP = 55°

And (QOR and SOP are central angles):

  • measure of arc QR, mQR = mQOR = 55°
  • measure of arc SP, mSP = mSOP = 55°

Finally:

measure of arc PQR, mPQR = mQOR + mSOP + mQOS = 55° + 55° + 125° = 235°

measure of arc RPQ, mRPQ = mROP + mSOP + mQOS = 125° + 55° + 125° = 305°

6 0
3 years ago
2
yawa3891 [41]

Answer:

a

Step-by-step explanation:

5 0
3 years ago
Find the length of the hypotenuse of the right triangle.
Klio2033 [76]

*☆*――*☆*――*☆*――*☆*――*☆*――*☆*――*☆*――*☆**☆*――*☆*――*☆*――*☆

Answer: 34

I hope this helped!

<!> Brainliest is appreciated! <!>

- Zack Slocum

*☆*――*☆*――*☆*――*☆*――*☆*――*☆*――*☆*――*☆**☆*――*☆*――*☆*――*☆

8 0
3 years ago
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