Answer:
There's going to be 2 solutions
Step-by-step explanation:
Apply the distributive property.<span>6⋅1+6<span>(−5m<span>)
</span></span></span>Multiply <span>66</span> by <span>11</span> to get <span>66</span>.<span><span>6+6<span>(−5m)</span></span><span>6+6<span>(-5m)</span></span></span>Multiply <span><span>−5</span><span>-5</span></span> by <span>66</span> to get <span><span>−30</span><span>-30</span></span>.<span><span>6−30m</span><span>6-30m</span></span>Reorder <span>66</span> and <span><span>−30m</span><span>-30m</span></span>.<span>−30m+<span>6
So your answer is </span></span>−30m+6
Answer:
i.e. relation between speed-distance-time is one such situation that can be modeled using graph
Step-by-step explanation:
There are many real world examples that can be modeled using graph. Graphs are represented on co-ordinate planes, so any real world example that can be represented by use of linear equation can be represented onto a graph.
One such example, is speed-distance-time relation. Uniform speed can be represented on a graph as shown in figure.
So, the equation for speed is represented by equation as follows:
So, if we take distance on y axis and time on x axis with points as (distance,time)
(0,0) ==> 
(1,2) ==> 
(2,2) ==> 
the following points 0,0.5,1 will be plotted on graph. Similarly, more values can be plotted by assuming values for distance and time.
Answer:
3.45
Step-by-step explanation:
15 percent of 23
15 percent to decimal = 0.15
23 x 0.15 = 3.45
Answer:
a). -65
b). -61
c). -20ab + 3bc +3ac
Step-by-step explanation:
According To the Question,
a). the sum of 72 − 104 + 5 and -32 + 4 - 10 .
- (72 − 104 + 5) + (-32 + 4 - 10)
- (-27) + (-38)
- -27 - 38
- -65
b). What should be added to 32 + 32 + 3 to get 3 + 3 , Let X be Added .
- Thus, (32 + 32 + 3) + X = 3 + 3
- 67 + X = 6
- X = 6 - 67
- X = -61
c). Subtract the sum of 12ab –10bc –18ac and 9ab + 12bc + 14ac from the sum of ab + 2bc and 3bc – ac.
- Thus, [(ab + 2bc) + (3bc – ac)] - [( 12ab –10bc –18ac) + (9ab + 12bc + 14ac)]
- (ab + 5bc - ac) - (21ab + 2bc - 4ac)
- ab + 5bc - ac - 21ab - 2bc + 4ac
- -20ab + 3bc + 3ac
