Add -7 to both sides so that the equation becomes -3x^2 + 6x + 2 = 0.
To find the solutions to this equation, we can apply the quadratic formula. This quadratic formula solves equations of the form ax^2 + bx + c = 0
x = [ -b ± √(b^2 - 4ac) ] / (2a)
x = [ -6 ± √((6)^2 - 4(-3)(2)) ] / ( 2(-3) )
x = [-6 ± √(36 - (-24) ) ] / ( -6 )
x = [-6 ± √(60) ] / ( -6)
x = [-6 ± 2*sqrt(15) ] / ( -6 )
x = 1 ± -sqrt(15)/3
The answers are 1 + sqrt(15)/3 and 1 - sqrt(15)/3.
Answer:
RTA= (x-2)·(x-11/2)/(x-2)(x-4)= (you can simplify again if you want by eliminating both (x-2)
(x-11/2)/(x-4)
Step-by-step explanation:
Ok we need to simplify the expression so:
x^2+3x-10= Bhaskara formula=
-3(±√9-4·1·(-10))/2·1=
X1=(-3+7/2)--> X1=2(R)---> (X-R)--->X-2
X2=(-3-7)/2 --> X2=11/2(R)---> (X-R)--->X-11/2
x^2-6x+8= Bhaskara formula=
6(±√36-4·1·8)/2·1=
X1=(6-2)/2=2--> X1=2(R)---> (X-R)--->X-2
X2=(6+2)/2=2--> X2=4(R)---> (X-R)--->X-4
so, The simplify expression is
(x-2)·(x-11/2)/(x-2)(x-4)=
<span>1, 2, 3, 5, 6, 10, 15, 30 represent the factors of 30, the GCF. </span>
If you have built 25 cars, and they are 36 dollars per, then multiply 25 and 36 for the amount of money. This will result with 25*36=900. Since we already have 900 dollars worth, we subtract that from the goal of 1620, leaving us with 1620-900=720. Now, divide this by the price per car for the amount of cars needed to get to this goal. 720/36=20 cars
Hope this helps!
j=4.88 when g=8 and v=11
Further explanation:
When the increase/decrease in one quantity cause increase/decrease in other quantity, it is called direct variation.
Variation is always accompanied by a variation constant.
<u>Given</u>
g and v vary directly with j
IT can be written as:
j∝gv
Putting the variation constant k
j = kgv
Putting g = 6 and v=3
So the value of k is 1/18 which makes the equation
So, j=4.88 when g=8 and v=11
Keywords: Variation, Direct Variation
Learn more about variation at:
#LearnwithBrainly
