Answer:
goldfish is 15 and guppies is 11
Step-by-step explanation:
Given data
let the number of goldfish be x
and the number of guppies be y
so
x+y= 25----------1
and
3x+4y= 86-------2
solve 1 and 2
x+y= 25
3x+4y= 86
from 1
x= 25-y
put this in 2
3(25-y)+4y= 86
75-3y+4y= 86
75+y= 86
y= 86-75
y=11
put y= 11 in 1
x+11= 26
x= 26-11
x= 15
Hence goldfish is 15 and guppies is 11
Answer:
Step-by-step explanation:
(x² + 6x + 9)(x)= x²*x + 6x*x + 9*x = x³ + 6x² + 9x
Answer:
3. 150.72 in²
4. 535.2cm²
Step-by-step Explanation:
3. The solid formed by the net given in problem 3 is the net of a cylinder.
The cylinder bases are the 2 circles, while the curved surface of the cylinder is the rectangle.
The surface area = Area of the 2 circles + area of the rectangle
Take π as 3.14
radius of circle = ½ of 4 = 2 in
Area of the 2 circles = 2(πr²) = 2*3.14*2²
Area of the 2 circles = 25.12 in²
Area of the rectangle = L*W
width is given as 10 in.
Length (L) = the circumference or perimeter of the circle = πd = 3.14*4 = 12.56 in
Area of rectangle = L*W = 12.56*10 = 125.6 in²
Surface area of net = Area of the 2 circles + area of the rectangle
= 25.12 + 125.6 = 150.72 in²
4. Surface area of the net (S.A) = 2(area of triangle) + 3(area of rectangle)
= 
Where,
b = 8 cm
h = ![\sqrt{8^2 - 4^2} = \sqrt{48} = 6.9 cm} (Pythagorean theorem)w = 8 cm[tex]S.A = 2(0.5*8*6.9) + 3(20*8)](https://tex.z-dn.net/?f=%20%5Csqrt%7B8%5E2%20-%204%5E2%7D%20%3D%20%5Csqrt%7B48%7D%20%3D%206.9%20cm%7D%20%28Pythagorean%20theorem%29%3C%2Fp%3E%3Cp%3Ew%20%3D%208%20cm%3C%2Fp%3E%3Cp%3E%5Btex%5DS.A%20%3D%20%202%280.5%2A8%2A6.9%29%20%2B%203%2820%2A8%29)



They will hold 112.25 cm^3 more. Find the volume of the second can with the new side lengths and subtract the orginal volume from the new one.
3/20, or 0.15 of the shirts each evening
1 - 1/4 = 3/4
(3/4) / 5 = (3/4) / (5/1) = (3/4) x (1/5) = 3/20 = 0.15