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zzz [600]
3 years ago
6

Ann's watch runs 2 minutes per hour too slow. Beth's watch runs 1 minute per hour too fast. For example, if both watches were co

rrect at 12p.m on a given day, then at 1:00PM, Ann's watch would read 12:58PM and Beth's would read 1:01 PM. Ann and Beth set their watches to the correct time at noon on Sunday. The next time they met, one of the watches was one hour ahead of the other. What was the earliest time this could have been?
Mathematics
1 answer:
Elenna [48]3 years ago
7 0

Answer:

8 am Monday

Step-by-step explanation:

The difference between the two watches is  2+1= 3 minutes.

It would take 60/3 = 20 hours to have a difference of 60 minutes.

From noon Sunday it would be more 20 hours the earliest time there would be a difference of one hour between the two watches' time.

12 noon + 20 hours=  8 am Monday

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Answer:

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Step-by-step explanation:

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I think there's an image needed to answer this question?

I tried answering without, but you do need the image.

If the length is 40 and the width is 25, the ration of length:width is 40:25.

This can be simplified to 8:5

So the answer would be any drawing with the following dimensions:

1. length 8 ft and width 5 ft

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It's most likely not the last 3 because the sizes are very big, but yeah a scale drawing maintains the same ratio so I assume one of the options for your answers is gonna be one of the answers from 1 - 4 above (5 is the given dimensions so I highly doubt that's the answer)

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Anvisha [2.4K]

Answer:

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Step-by-step explanation:

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Ierofanga [76]

Answer:

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Step-by-step explanation:

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Answer:
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