1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
77julia77 [94]
3 years ago
6

Write f(2)=-3 as a coordinate point

Mathematics
1 answer:
kondaur [170]3 years ago
4 0

Answer:

(2,-3)

Step-by-step explanation:

You might be interested in
Where does the graph of y = sin x from x = 0 to x = 2π start?
Bad White [126]

the graph starts at an x intercept.

6 0
3 years ago
Read 2 more answers
For the graph, locate the x-intercept and the y-
chubhunter [2.5K]
X intercept= 6
y intercept= -2
7 0
3 years ago
Find the value of the variable if P is between J & K. A) JP = 8z - 17 B) PK = 5z + 37 C) JK = 17z - 4
Daniel [21]
<span>We cannot deduce about the exact location of P between J and K. But we can conclude: segment JP + segment PK = line JK.
</span><span>JP + PK = JK.
</span><span>Substitute first each.
(8z - 17) + (5z + 37) = 17z - 4
Combine like terms.
13z + 20 = 17z - 4
Isolate the variable z.
4z = 24
z = 6
The value of the variable z is then 6 units.</span>
3 0
3 years ago
Read 2 more answers
What is the total surface area of the square pyramid below?
AVprozaik [17]

Answer:

D

Step-by-step explanation:

380

3 0
3 years ago
Triangle $ABC$ has a right angle at $B$. Legs $\overline{AB}$ and $\overline{CB}$ are extended past point $B$ to points $D$ and
Lisa [10]

Answer:

Given :

ABC is a right triangle in which ∠ABC = 90°,

Also, Legs AB and CB are extended past point B to points D and E,

Such that,

\angle EAC = \angle ACD = 90^{\circ}

To prove :

EB\times BD=AB\times BC

Proof :

In triangles AEC and EBA,

∠EAC= ∠ABE ( right angles )

∠CEA = ∠AEB ( common angles )

By AA similarity postulate,

\triangle AEC \sim \triangle EBA,

Similarly,

\triangle AEC \sim \triangle ABC

\implies\triangle EBA\sim \triangle ABC-----(1)

Now, In triangles ADC and CBD,

∠ACD = ∠CBD ( right angles )

∠ADC= ∠BDC ( common angles )

By AA similarity postulate,

\triangle ADC \sim \triangle CBD,

Similarly,

\triangle ADC \sim \triangle ABC

\implies \triangle CBD\sim \triangle ABC-----(2)

From equations (1) and (2),

\triangle EBA\sim \triangle CBD

The corresponding sides of similar triangles are in same proportion,

\frac{EB}{BC}=\frac{AB}{BD}

\implies EB\times BD=AB\times BC

Hence, proved....

5 0
3 years ago
Other questions:
  • What is 6 to the second power divided by 2(3)+4=
    8·2 answers
  • What percent of 137.4 is 96
    5·1 answer
  • All numbers divisible by 100 are divisible by 25.
    6·1 answer
  • Please solve this equation much appreciated
    10·2 answers
  • the temperature on saturday was 4 degrees Fahrenheit F the temperature on sunday was 9 degrees warmer than the temperature on sa
    12·2 answers
  • Solve the inequality and graph the solution set on a number line.<br> ​ −50≤7x+6&lt;−8
    11·1 answer
  • Which expression is equivalent to 2(4x + 7)?
    11·2 answers
  • What is the greatest common factor for 12 and 54? enter your answer in the box.
    7·2 answers
  • C increased by 8 can I get help
    9·1 answer
  • 25° 35° to 205° circle ​
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!