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3 years ago

How do I solve this?

Mathematics

1 answer:

Zepler [3.9K]3 years ago

5 0

X + 3/2 = x - 1/5

We multiply both sides of the equation by the LCM which is 10
10 × x + 3/2 = 10 × x - 1/5

5 (x + 3) = 2 (x - 1)
We expand the brackets

5x + 15 = 2x - 2

5x - 2x = -2 -15

3x = -17

x = -17/3
Therefore x = -17/3

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Is -6 over 7 a whole number a integer number or a rational number

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Answer:

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Step-by-step explanation:

It is a rational number because -6/7 is equal to -0.857142 repeating. And a rational number repeats.

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krok68 [10]

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2 years ago

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Find the inverse of ????−7 −2

Masja [62]

Answer:

$A^{-1}=\begin{bmatrix}1 & 2\\ -4 & -7\end{bmatrix}$

Step-by-step explanation:

$A=\begin{bmatrix}-7 & -2\\ 4 & 1\end{bmatrix}$

$det\ A=-7\times 1-(-2)\times 4\\\Rightarrow det\ A=1$

$A^{-1}=\frac{1}{det\ A}\begin{bmatrix}1 & 2\\ -4 & -7\end{bmatrix}\\\Rightarrow A^{-1}=\frac{1}{1}\begin{bmatrix}1 & 2\\ -4 & -7\end{bmatrix}\\\Rightarrow A^{-1}=\begin{bmatrix}1 & 2\\ -4 & -7\end{bmatrix}$

$\therefore A^{-1}=\begin{bmatrix}1 & 2\\ -4 & -7\end{bmatrix}$

$A.A^{-1}=\begin{bmatrix}-7 & -2\\ 4 & 1\end{bmatrix}\times \begin{bmatrix}1 & 2\\ -4 & -7\end{bmatrix}\\\Rightarrow A.A^{-1}=\begin{pmatrix}\left(-7\right)\cdot \:1+\left(-2\right)\left(-4\right)&\left(-7\right)\cdot \:2+\left(-2\right)\left(-7\right)\\ 4\cdot \:1+1\cdot \left(-4\right)&4\cdot \:2+1\cdot \left(-7\right)\end{pmatrix}\\\Rightarrow A.A^{-1}=\begin{pmatrix}1&0\\ 0&1\end{pmatrix}$

Hence, confirmed

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Step-by-step explanation:

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