Answer:
Yes, this set of lengths can form a triangle.
Step-by-step explanation:
55+76 = 131
131 > 112
Since the sum of smaller lengths is greater than 112, these numbers can form a triangle.
Answer:
Step-by-step explanation:
Area of circle = 56 cm²
πr² = 56
3.14r² = 56
r²=56/3.14
r²= 17.83
r = √17.83
r = 4.22 cm
The diameter of the circle = diagonal of the square
Diagonal of the square = 2 * 4.22 = 8.44 cm
x² + x² = 8.44²
2x² = 71.2336
x² = 71.2336/2
x² = 35.6168
x = 5.967 cm
The illegal values of b are when the denominator equals 0.
So, 
gives you (b-4)(b+2)=0
Therefore, b=4 and b=-2, which is answer A.
I'm not sure about this but will give it a try:
Let f(n) = 2xⁿ - 2
Then f(3) = 2x³ - 2
So, f(2) = 2x² - 2
