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3 years ago

Does anybody know how to do this??

Mathematics

1 answer:

boyakko [2]3 years ago

3 0

just divide 200 until u get 25 i think but idk the second one

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2,6,12,16,32,36,72 complete the number pattern

deff fn [24]

Answer:

Next is 76, 82, 86, and 92

Step-by-step explanation:

4 0

3 years ago

Find x in this proportion. 5/2x =25/4 x = 2/5 5/2 4/5 8/5

Ymorist [56]

Answer:

2/5

Step-by-step explanation:

make it reciprocal

2x/5 = 4/25

cross multiply the numbers

2x × 25 = 4×5

2x= 20/25

2x= 4/5

x = 2/5

4 0

3 years ago

Express 81 as the sum of first nine consecutive odd numbers

matrenka [14]

Answer:

see explanation

Step-by-step explanation:

The sum of the first 9 consecutive odd numbers is

1 + 3 + 5 + 7 + 9 + 11 + 13 + 15 + 17 = 81

3 0

3 years ago

Lin runs 5 laps around a track in 6 minutes.

Paladinen [302]

Answer:

25.2

Step-by-step explanation:

6/5 is 1.2, so it takes 1.2 minutes to run one lap.

This means 21 x 1.2 = the minutes it takes to run 21 laps around the track.

Therefore it takes 25.2 minutes to run around the track 21 times.

3 0

2 years ago

HURRYYYYYYYYY!! What is the equation of the quadratic function with a vertex at (2, 25) and an x-intercept at (7,0)?

tangare [24]

Answer:

$y=-(x-7)(x+3)$

which is none of the choices provided.

Are you sure the question is right or even the choices?

You can even write it as:

$y=-(x+3)(x-7)$ but this is still not a choice.

Step-by-step explanation:

The vertex form of a quadratic is $y=a(x-h)^2+k$ .

This is called vertex form because it gives you the vertex is $(h,k)$ .

We are given that $(h,k)=(2,25)$ which makes our equation:

$y=a(x-2)^2+25$ .

We can find the value of $a$ by plugging in the x-intercept (7,0) for $(x,y)$ into:

$y=a(x-2)^2+25$

$0=a(7-2)^2+25$

$0=a(5)^2+25$

Subtract 25 on both sides:

$-25=a(5)^2$

$-25=a(25)$

Divide both sides by 25:

$\frac{-25}{25}=a$

$-1=a$ .

So the equation for the quadratic is:

$y=-1(x-2)^2+25$

Let's put this into factored form since all the choices are in factored form.

This will require us to multiply the (x-2)(x-2) out:

$y=-1(x-2)(x-2)+25$

$y=-1(x^2-2x-2x+4)+25$

$y=-1(x^2-4x+4)+25$

$y=-x^2+4x-4+25$

$y=-x^2+4x+21$

Factor out -1:

$y=-(x^2-4x-21)$

WE need to find two numbers that multiply to be -21 and add to be -4:

$y=-(x-7)(x+3)$

8 0

3 years ago

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