Which of the following is true about the graphs below?

Find the product of 27×6×60 then explain how you would use mental math to find the product of 27×600

Ne4ueva [31]

27x6x60=9,720 *You can use mental math by multiplying 27 by 6 and adding the 2 zeros to the end of the product*

7 0

2 years ago

Which equation represents the statement: Three times the sum of a number and 5 is –30?

castortr0y [4]

Answer:

3(n+5)=-30

Step-by-step explanation:

Three times the sum of a number and 5 is - 30

Vocabulary:

times = multiplication, represented with *

sum = addition, represented by +

unknown number = n

Three * the sum of a number and 5

The sum of a number and 5 is the same as saying n + 5

So we are multiplying 3 by n + 5

Because n is an unknown variable we have to separate the sum of n and 5 from being multiplied by 3 with parenthesis. We do this because if we want to multiply 3 by the sum of n and 5. If we put 3 * n + 5 we are only multiplying the unknown variable by 3 not including the 5 that is added to it.

So we get 3( n + 5 ) is -30

3(n+5)=-30 is the answer.

3 0

2 years ago

Read 2 more answers

A sample of tritium-3 decayed to 94.5% of its original amount after a year.

Zolol [24]

(a) If $y(t)$ is the mass after $t$ days and $y(0) = A$ then $y(t) = Ae^{kt}.$

$y(1) = Ae^k = 0.945A \implies e^k = 0.945 \implies k = \ln 0.945$

$\text{Then } Ae^{(\ln 0.945)t} = \frac{1}{2}A\ \Leftrightarrow\ \ln e^{(\ln 0.945)t} = \ln \frac{1}{2}\ \Leftrightarrow\ ( \ln 0.945) t = \ln \frac{1}{2} \Leftrightarrow \\ \\
t = - \frac{\ln 5}{\ln 0.945} \approx 12.25 \text{ years}$

(b)
$Ae^{(\ln 0.945) t} = 0.20 A \ \Leftrightarrow\ (\ln 0.945) t \ln \frac{1}{5}\ \implies \\ \\
t = - \frac{\ln 5}{\ln 0.945} \approx 28.45\text{ years}$

3 0

3 years ago

What is the final amount if 975 is increased by 1% followed by a further 9% increase?

alexgriva [62]

975 x 1.01 = 984.75
984.75 x 1.09 = 1073.38

3 0

3 years ago

What is the relationship between the conversion factors used in Part A of Model 2? Whatabout the conversion factors used in Part

Lelu [443]

Given:

The conversions from meter to inches and inches to meter are shown in part A of model 2.

The conversions from liters to quarts and quarts to liters are shown in part B of model 2.

Required:

To find the relationship between the conversion factors used in Part A of Model 2.

To find the relationship in the the conversion factors used in Part B of Model 2.

Explanation:

We have given that 1 meter = 39.4 inches.

Thus, from the calculations shown in part A of model 2, we can conclude that the quantity from meters to inches is converted as:

$1.5\times39.4=59$

Thus, 1.5 m =59 inches.

Also, the quantity from inches to meters is converted as:

$\frac{59}{39.4}=1.5$

Hence, 59 in = 1.5 m.

Next,

We have 1 L = 1.06 qt.

Thus, from the calculations shown in part B of model 2, we can conclude that the quantity from quarts to liters is converted as:

$\frac{186}{1.06}=175$

Thus, 186 quarts = 175 L.

Also, the quantity from liters to quarts is converted as:

$175\times1.06=186$

Hence, 175 L = 186 qt.

Final Answer:

We conclude that:

While converting from meters to inches, we multiply the quantity 1.5 by the equality quantity given.

While converting from incehs to meters, we divide the quantity 59 by the equality quantity given.

Also, While converting from quarts to liters, we divide the quntity 186 by the equality quantity given.

While converting from liters to quarts, we multiply the quntity 175 by the equality quantity given.

6 0

1 year ago