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Elena-2011 [213]
4 years ago
9

Write square root of 64 minus square root of -289 as a complex number in the form of a +bi .

Mathematics
1 answer:
Alex777 [14]4 years ago
5 0

Answer:

8 - 17i

Step-by-step explanation:

\sqrt{64} is real = 8

\sqrt{-289} is imag = 17i

8 - 17i

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Nitella [24]
We see that we have some nasty sqrt signs
try to use x values that yield perfect squares inside the sqrt sign like 1,4,9,16, or ones that make the inside 0


first one

y=-4+√(x+2)
try some nice values for ease of graphing

ok so try x=-2
y=-4
(-2,-4)

x=-1
y=-3
(-1,-3)

x=-1
y=-3
(-1,-2)

if x=7
y=-1
(7,-1)

if x=14
y=0
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so we have
(-2,-4)
(-1,-3)
(2,-2)
(7,-1)
(14,0)




second one
y=2+√(x+1)


if x=-1
y=2
(-1,2)

if x=0
y=3
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if x=3
y=4
(3,4)

if x=8
y=5
(8,5)

we have

(0,3)
(-1,2)
(3,4)
(8,5)












 
first one
y=-4+√(x+2)
so we have
(-2,-4)
(-1,-3)
(2,-2)
(7,-1)
(14,0)

second one
y=2+√(x+1)
(0,3)
(-1,2)
(3,4)
(8,5)

7 0
3 years ago
Read 2 more answers
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