Answer:
B) No, because the p-value is greater than any reasonable significance level
Step-by-step explanation:
H-null: p = 0.41
H-alt: p =/= 0.41
1 proportion Z test
On a calculator: stat + tests + 5
p: .41
x: 245
n: 600
prop: =/= p
This gives a p-value = .934
(standard significance level is .05, so this p-value is much larger)
fail to reject H-null
Answer:
Step-by-step explanation:
Hopes this helps if it don’t than sorry:
Answer: p + 5 - 7q
