17% of the total number of students are in 1st grade
→0.17×500=85 students in 1st grade
19% of the total number of students are in 4th grade
→0.19×500=95 students in 4th grade
<span>The number of 3rd-grade students is 9 less than the number of 4th-grade students.
→95-9=86 students in 3rd grade
</span><span>The number of 2nd-grade students is 10 less than the number of 5th-grade students.
1st grade+4th grade+3rd grade=85+95+86=266
500-266=234=total number of students in 2nd grade and 5th grade
Let x=2nd grade students
Let y=5th grade students
x+y=234
2nd grade students is 10 less than the number of 5th grade students
→x=y-10
Since x=y-10 so we substitute y-10 for x
→y-10+y=234
→2y-10=234
+10 +10
→2y=244
→2y/2=244/2
→y=122 students in 5th grade
x+y=234
→x+122=234
→x=112 students in 2nd grade
ANSWERS:
1st: 85
2nd: 112
3rd: 86
4th: 95
5th: 122
</span>
Answer:
The distance between two points is √169 or 13.
Step-by-step explanation:
In the question we need to find the distance between two points 5,6 and 0,-6 given.
Distance between two points can be found using the formula:
Putting the given points in the formula we get,
x₂ = 0, x₁ = 5, y₂= -6, y₁= 6
So, the distance between two points is √169 or 13.
Answer:
3
Step-by-step explanation:
see image below:)
Answer:
90gr strawberry jelly
6 sponge fingers
315ml custard
135gr tinned fruit
Step-by-step explanation:
120/4 = 30 * 3 = 90
8/4 = 2 * 3 = 6
420/4 = 105 * 3 = 315
180/4 = 45 * 3 = 135
Answer:
2) 360 square inches
Step-by-step explanation:
First of all we have to verify that the base triangle is a right triangle
For this we use Pythagoras
h² = l1² + l2²
13² = 12² + 5²
169 = 144 + 25
169 = 169
Equality is fulfilled by what is a right triangle
Now we need to calculate the area of the triangle
a = (12 in * 5 in) / 2
a = 60in² / 2
a = 30in²
Now we have to calculate the 3 areas of the rectangles
a1 = 10in * 13 in
a1 = 130in²
a2 = 10 in * 12 in
a2 = 120in²
a3 = 10 in * 5 in
a3 = 50in²
Now we must add all the calculated areas and the triangle 2 times
a1 + a2 + a3 + 2a =
130in² + 120in² + 50in² + 2 * 30in²
360in²
The surface area of the prism is 360in²
