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Marysya12 [62]
3 years ago
6

If each pretzels weighed a half an ounce, how many pretzels would fit in a 16 ounce bag

Mathematics
2 answers:
OLEGan [10]3 years ago
6 0
32 pretzels because since each pretzel wieghs 1/2 an ounce you multiply 16x 2=32
Murrr4er [49]3 years ago
4 0
To find out we should, divide the whole weight to weight of each pretzels.

The whole is 16 ounce and each pretzel is \frac { 1 }{ 2 } ounces. So let's divide :

\frac { 16 }{ \frac { 1 }{ 2 }  } \\ \\ We\quad can\quad rewrite\quad \\ this\quad expression\quad as\quad :\\ 16\cdot \frac { 2 }{ 1 } \\ and\quad that\quad is\quad equal\quad to\\ 16\cdot 2=32\\ \\ \\

When you divide a number by a fraction, you can flip the fraction upside down and multiply it with the number, the result will be same.

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X*2+1=10 then x=? Tell me the value of x
Trava [24]

Answer:

<h2>4.5</h2>

Step-by-step explanation:

x \times 2 + 1 = 10

2x +  1 = 10

Move constant to R.H.S and change its sign

2x = 10 - 1

Subtract the numbers

2x = 9

Divide both sides of the equation by 2

\frac{2x}{2}  =  \frac{9}{2}

Calculate

x = 4.5

Hope this helps..

Best regards!!

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3 years ago
Help my friends y'all really are awesome
anyanavicka [17]

Answer:

81

Step-by-step explanation:

u multiply 9 x 9 not 9x2

5 0
3 years ago
51. Find the length of the unknown side x of this triangle, evaluate your answer to two decimal places.
KiRa [710]

Answer:

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Step-by-step explanation:

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4 0
2 years ago
Read 2 more answers
What is the value of y in this system of equations: 3x + y = 9 y = –4x + 10 ?
Ahat [919]
<span>3x + y = 9 (I)
</span><span>y = –4x + 10 (II)
------------------------
</span>\left \{ {{3x + y = 9 } \atop {y = -4x + 10 }} \right.

Pass the incognito "4x" to the first term, changing the signal when changing sides.
<span>-------------------------
simplify by (-1)
</span>\left \{ {{3x + y = 9.(-1)} \atop {4x + y = 10 }} \right.<span>

-------------------------
</span>\left \{ {{- 3x - \diagup\!\!\!\!y =-9} \atop {4x + \diagup\!\!\!\!y = 10}} \right.     &#10;
<span>
-------------------------
</span>\left \{ {{- 3x = - 9} \atop {4x = 10}} \right.<span>

-----------
</span>\boxed{x = 1}<span><span>

</span></span><span>Substitute in equation (I) to find the value of "Y".

</span>3x + y = 9 (I)
3*(1) + y = 9
3 + y = 9
y = 9 - 3
\boxed{y = 6}

Answer:
\boxed{\boxed{ \left \ {{x=1} \atop {y=6}} \right. }}

6 0
3 years ago
Could somebody check my work and tell me if it's right? If its wrong, please tell me where I went wrong.
vodka [1.7K]

Answer:

it would help if we could see it

4 0
3 years ago
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