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Iteru [2.4K]
3 years ago
11

A shopper bought shoes marked $40 the sales tax is 8%. How much did the shopper pay in all?

Mathematics
1 answer:
s2008m [1.1K]3 years ago
8 0

Answer:

$43.20

Step-by-step explanation:

0.08*40=3.2

3.2+40=$43.20

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Consider the line y=5x-4.
Bezzdna [24]

Answer:

Parallel= y-5x-3

perpendicular=y=5x

Step-by-step explanation:

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CORRECT ANSWER GETS BRAINLIST
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If philani buys a scooter for 15,000 and wants to pay 15% down then he must pay 2,250. After this they will still need to pay 12,750 to pay of the scooter, but after the 10% annually (for two years) then they will owe 15,750 for the scooter rather than 12,750. Hope this helps!
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How would I set up the equation to find mRQS on this circle?
Leni [432]
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3 years ago
What is an equation of the line that passes through the point (-2,7) and is perpendicular to the line x-6y=42 ?
Natali5045456 [20]

Answer:

The equation of the line that passes through the point (-2,7) and is perpendicular to the line x-6y=42 is

6x+y=-5

Step-by-step explanation:

Given:  

Let,  

point A( x₁ , y₁) ≡ ( -2 , 7)

To Find:  

Equation of Line  that passes through the point (-2,7) and is perpendicular to the line x-6y=42=?  

Solution:  

x-6y=42    ..................Given

which can be written as

y=mx+c

Where m is the slope of the line

∴ y=\dfrac{x}{6}-7

On Comparing we get

Slope = m = \dfrac{1}{6}

The Required line is Perpendicular to the above line.

So,

Product of slopes = - 1

m\times m_{1}=-1\\Substituting\ m\\ \dfrac{1}{6} m_{1}=-1\\\\m_{1}=-6

Slope of the required line is -6

Equation of a line passing through a points A( x₁ , y₁) and having slope m is given by the formula,  

i.e equation in point - slope form

(y-y_{1})=m(x-x_{1})

Now on substituting the slope and point A( x₁ , y₁) ≡ ( -2, 7) and slope = -6 we get

(y-7)=-6(x--2)=-6(x+2)=-6x-12\\\\\therefore 6x+y=-5.......is\ the required\ equation\ of\ the\ line

The equation of the line that passes through the point (-2,7) and is perpendicular to the line x-6y=42 is

6x+y=-5

3 0
3 years ago
Find fg(x) <br><img src="https://tex.z-dn.net/?f=f%28x%29%20%3D%20%20%7Bx%7D%5E%7B2%7D%20%20%2B%202" id="TexFormula1" title="f(x
Kipish [7]

Answer:

f(g(x)) = x^4 + 12x^3 + 14x^2 -132x + 123

Step-by-step explanation:

Here, we simply will place g(x) into f(x)

So every x in f(x) is replaced by g(x)

Thus, we have;

(x^2 + 6x + 11)^2 + 2

= (x^2+6x-11)(x^2 + 6x -11) + 2

= x^4 + 6x^3 -11x^2 + 6x^3 + 36x^2 - 66x -11x^2 -66x + 121 + 2

= x^4 + 12x^3 + 14x^2 -132x + 123

7 0
2 years ago
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