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denpristay [2]
2 years ago
11

In the diagram below, BE ~ BC, mLC = 32° and m/BFD = 103°. Find m

Mathematics
1 answer:
steposvetlana [31]2 years ago
5 0

Answer:

Here's a rainbow of logic.

Step-by-step explanation:

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a population of 140000 grows 4% per year for 16 years. How much will the population be after 16 years?
Igoryamba
At the end of the Year 1 the population will be = 110,000 + 4% of 110,000 =P1At the end of the Year 2 the population will be=P1+ 4% of P1= 110,000 + 4% of 110,000 + 4% of (110,000 + 4% of 110,000) =  110,000 +  4% of (110,000+ 110,000 + 4% of 110,000) =  110,000 + 2*4% of 110,000 + (4%)2  of 110,000= P2At the end of the Year 3 the population will be= P2+ 4% of P2= 110,000 +2* 4% of 110,000 + (4%)2 of 110,000 + 4% of [ 110,000 +2* 4% of 110,000 + (4%)2 of 110,000] = 110,000 +2* 4% of 110,000 + (4%)2 of 110,000 + 4% of 110,000 + 2* (4%)2 of 110,000 + (4%)3 of 110,000 =110,000 +3* 4% of 110,000 +3* (4%)2 of 110,000 + (4%)3 of 110,000 =P3At the end of the Year 4 the population will be= P3+ 4% of P3=110,000 +3* 4% of 110,000 +3* (4%)2 of 110,000 + (4%)3 of 110,000 +4% of [110,000 +3* 4% of 110,000 +3* (4%)2 of 110,000 + (4%)3 of 110,000] =110,000 +4* 4% of 110,000 + 6*(4%)2 of 110,000+4* (4%)3 of 110,000+ (4%)4 of 110,000 Now if we substitute n for 110,000 and r for 4% yearly rate of increase, we can rewrite,Before Year 1, at Year 0, the population, P0= n = n(1+r)0At the end of the Year 1 the population , P1= n+rn= x(1+r)1At the end of the Year 2 the population , P2= n+2rn+r2n =n(1+2r+r2)=n(1+r)2At the end of the Year 3 the population , P3= n+3rn+2r2n+r3n=n(1+3r+3r2+r3)=x(1+r)3At the end of the Year 4 the population , P4= n+4rn+6r2n+4r3n+r4n=n(1+r)4.
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At the end of the Year n the population , Px=n+nrx+(x-1)r2n+(x-2)r3n+...........+(x-x+2)r(x-1)x+(x-x+1)rxn=n(1+r)x.....At the end of the Year 16 the population , P16= n+16rn+15r2n+14r3n+.............+3r14n+2r15n+r16n=n(1+r)16 Thus under given condition of rate of growth, the Population P(x) at xth year will be P(x)=n(1+r)x Therefore, a population of 110,000 growing at 4% per year, in 16 years will be= 110,000(1+4/100)16= 110,000(1.04)16=206027.93702999115428132473599427≈206028

I hope this is helpful. I found the solution on the internet. Hope you have a good day and bye.
3 0
3 years ago
Miracle Printers incurred external costs of $ 1 comma 400 comma 000 for a patent for a new laser printer. Although the patent gi
dedylja [7]

Answer:

Ok, but this isn't a problem though, It is only a statement

Step-by-step explanation:

4 0
3 years ago
Change each fraction or mixed number to a percent. a. 2/5 b. 7/20 c. 1 11/16 d. 14 1/4
QveST [7]

Answer:

a. 20% b. 35% c. 1.6875 d. 14.25

8 0
2 years ago
Read 2 more answers
Least to greastest awnser
Morgarella [4.7K]

2) -88, -45, 5, 40

4) -45, -31, 20, 49

6) -74, -63, -45, 38

8) 18, 27, 27, 58

10) -60, -49, -40, 9

12) -45, -18, 80, 82

The bigger negative numbers are the least because negative numbers work the opposite way around of positive numbers. :)

8 0
2 years ago
I really need the answer to this
bezimeni [28]

Answer:

$350

Step-by-step explanation:

9550-9200=350

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