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jeka57 [31]
4 years ago
8

Choose the product.

Mathematics
1 answer:
Ivanshal [37]4 years ago
4 0

Answer:

first option

Step-by-step explanation:

Given

(3x² + 2x - 3)(x - 1)

Each term in the second factor is multiplied by each term in the first factor, that is

3x²(x - 1) + 2x(x - 1) - 3(x - 1) ← distribute parenthesis

= 3x³ - 3x² + 2x² - 2x - 3x + 3 ← collect like terms

= 3x³ - x² - 5x + 3

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To find the x-int., let y = 0 and solve for x:  13x = 6, so x = 6/13:  (6/13, 0)

To find the y-int., let x =0 and read off the y-int:  (0, -6)
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5 0
3 years ago
Which of the following functions is graphed below?
dalvyx [7]

Answer:

The function graphed is y = Ix - 5I - 4 ⇒ answer D

Step-by-step explanation:

* Lets explain how to solve this problem

- From the graph

# The graph intersects the x-axis at x = 1 and x = 9

∴ The x-intercepts are 1 and 9

- We can find x-intercept by equate y by 0

* Lets equate the answers by zero to find the x-intercept

# y = Ix + 5I - 4

∵ Ix + 5I - 4 = 0

- Add 4 to both sides

∴ Ix + 5I = 4

- Remember in Ia + bI = c, then we have two answers :

 a + b = c  <em>OR </em> a + b = -c

∵ Ix + 5I = 4

∴ x + 5 = 4 ⇒ subtract 5 from both sides

∴ x = -1

- OR

∴ x + 5 = -4 ⇒ subtract 5 from both sides

∴ x = -9

∴ The x-intercepts are -1 and -9 not the same with figure

# y = Ix - 5I + 4

∵ Ix - 5I + 4 = 0

- Subtract 4 from both sides

∴ Ix - 5I = -4

- Remember in Ia + bI = c , c can't be negative because the absolute

 value is always positive

∴ We can't solve this equation

# y = Ix + 5I + 4

∵ Ix + 5I + 4 = 0

- Subtract 4 from both sides

∴ Ix + 5I = -4

- Remember in Ia + bI = c , c can't be negative because the absolute

 value is always positive

∴ We can't solve this equation

# y = Ix - 5I - 4

∵ Ix - 5I - 4 = 0

- Add 4 to both sides

∴ Ix - 5I = 4

- Remember in Ia + bI = c, then we have two answers :

 a + b = c  <em>OR </em> a + b = -c

∵ Ix - 5I = 4

∴ x - 5 = 4 ⇒ add 5 to both sides

∴ x = 9

- OR

∴ x - 5 = -4 ⇒ add 5 to both sides

∴ x = 1

∴ The x-intercepts are 1 and 9 the same with figure

* The function graphed is y = Ix - 5I - 4

5 0
3 years ago
5x-22 3x +105 x minus 22 3 X + 10 ​
Mila [183]

-291x+10

:)))))) Have fun

7 0
3 years ago
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