Step-by-step explanation:
the 2nd expression is the answer
Answer:
If we have a set of N elements:
{x₁, x₂, ..., xₙ}
The mean value (also called the average value) Is calculated as:
Average = (x₁ + x₂ + ... + xₙ)/n
So if x is the average of 13, -16 and 6 ( a total of 3 values)
x will be equal to:
x = (13 + (-16) + 6)/3 = (19 - 16)/3 = 3/3 = 1
x = 1
And we know that:
y = ∛8
Remember that:
2*2 = 4
and
4*2 = 8
then
2*2*2 = 2^3 = 8
then ∛8 = 2.
So we have:
y = ∛8 = 2
Now we can replace these values in the equation:
x^2 + y^3
replacing:
x = 1
y = 2
we get:
1^2 + 2^3 = 1 + 8 = 9
Answer:
The answer you are looking for is x = 3/10
Step-by-step explanation:
D( x )
x = 0
x = 0
x = 0
x in (-oo:0) U (0:+oo)
72/x = 3.6/0.015 // - 3.6/0.015
72/x-(3.6/0.015) = 0
72/x-240 = 0
72*x^-1 = 240 // : 72
x^-1 = 10/3
-1 < 0
1/(x^1) = 10/3 // * x^1
1 = 10/3*x^1 // : 10/3
3/10 = x^1
x = 3/10
x = 3/10
