For this simulation, there are 5 numbers that we can draw. One of the numbers will result in seeing the groundhog. (1/5 or 0.20) To find the probability that Jay will see the groundhog 4 years in a row, we would use the following equation: 1/5•1/5•1/5•1/5
We would multiply the odds of getting a certain outcome by the number of time we want that outcome.
The odds that Jay will see the groundhog for the next for years is 0.0016, or .16%.
Answer:
x=3
Step-by-step explanation:
4-2x-4=-2-4
-2x=-6
\frac{-2x}{-2}=\frac{-6}{-2}
x=3
if i can get brainliest that would be great
Rearrange the equation to standard form of a quadratic equation (ax^2+bx+c=0) by switching sides: 5x^2+2x-12=0. Now, use the quadratic equation formula to solve. You should come out with x_1=sqrt61-1/5 and x_2=-1+sqrt61/5. Thus, your answer is B, or two solutions.
