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Varvara68 [4.7K]
3 years ago
12

If y = 18, when x = 12, find y when x = 36.

Mathematics
1 answer:
love history [14]3 years ago
4 0

Answer:

x = 36, y = 54.

Step-by-step explanation:

So if x = 36 and y = ?,

Its the same as x = 12, and y = 18.

36 / 12 = 3

That means y / 18 = 3.

Lets reverse this and make it a multiplication problem.

18 x 3 = y.

18 x 3 = 54.

So if x = 36, y = 54.

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25+ Points -- Photo Provided...
Readme [11.4K]

Answer:

-3, 8

Step-by-step explanation:

-x² + 5x + 24 = 0

-x² + 8x - 3x + 24 = 0

-x(x - 8) - 3(x - 8) = 0

(-x - 3)(x - 8) = 0

x = -3 , 8

3 0
3 years ago
Which situation will have the greatest number of permutations?
Anton [14]

Answer:

Option C will have greatest number of permutations.

Step-by-step explanation:

A.

The number of license plates with 4 letters followed by 3 numbers, where letters and digits cannot be repeated.

We have total 26 letters (A_Z) and the letters can't be repeated. So we have 26 letter options for 1st letter

25 letters options for 2nd letter

24 letter options for 3rd letter

23 letter options for 4th letter.

So total options for 4 letters 26*25*24*23 = 358800

Now, 3 numbers are required. We have total 10 numbers (0-9)

10 number options for 1st number

9 number options for 2nd number

8 number options for 3rd number

Total options for 3 numbers= 10*9*8 = 720

total options for 4 letters and 3 numbers will be: 358800 * 720 = 258,336,000

B.

The number of license plates with 3 letters followed by 4 numbers, where letters and digits cannot be repeated.

We have total 26 letters (A_Z) and the letters can't be repeated. So we have 26 letter options for 1st letter

25 letters options for 2nd letter

24 letter options for 3rd letter

So total options for 3 letters= 26*25*24 = 15600

Now, 4 numbers are required. We have total 10 numbers (0-9)

10 number options for 1st number

9 number options for 2nd number

8 number options for 3rd number

7 number options for 4th number

Total options for 4 numbers = 10*9*8*7 = 5040

total options for 4 letters and 3 numbers will be: 15600 * 5040 = 78,624,000

C. The number of license plates with 4 letters followed by 3 numbers, where letters and digits can be repeated.

Now, the letters and digits can be repeated. So we have 26 options for each 4 letters and 10 options for each 3 numbers

26*26*26*26 *10*10*10 = 456,976 * 10,00 = 456,976,000

total options for 4 letters and 3 numbers will be: 456,976,000

D.

The number of license plates with 3 letters followed by 4 numbers, where letters and digits can be repeated.

Now, the letters and digits can be repeated. So we have 26 options for each 3 letters and 10 options for each 4 numbers

26*26*26 *10*10*10*10 = 17,576 * 10,000 = 175,760,000

total options for 3 letters and 4 numbers will be: 175,760,000

So, Option C will have greatest number of permutations.

7 0
3 years ago
Discrete R.V. Assume a student shows up for EGR 280 completely unprepared and the instructor gives a pop quiz. Assume there are
Tom [10]

Answer:

a) p=0.2

b) probability of passing is 0.01696

.

c) The expected value of correct questions is 1.2

Step-by-step explanation:

a) Since each question has 5 options, all of them equally likely, and only one correct answer, then the probability of having a correct answer is 1/5 = 0.2.

b) Let X be the number of correct answers. We will model this situation by considering X as a binomial random variable with a success probability of p=0.2 and having n=6 samples. We have the following for k=0,1,2,3,4,5,6

P(X=k) = \binom{n}{k}p^{k}(1-p)^{n-k} = \binom{6}{k}0.2^{k}(0.8)^{6-k}.

Recall that \binom{n}{k}= \frac{n!}{k!(n-k)!} In this case, the student passes if X is at least four correct questions, then

P(X\geq 4) = P(X=4)+P(X=5)+P(X=6)=\binom{6}{4}0.2^{4}(0.8)^{6-4}+\binom{6}{5}0.2^{5}(0.8)^{6-5}+\binom{6}{6}0.2^{6}(0.8)^{6-6}= 0.01696

c)The expected value of a binomial random variable with parameters n and p is E[X] = np. IN our case, n=6 and p =0.2. Then the expected value of correct answers is 6\cdot 0.2 = 1.2

5 0
4 years ago
The equation of the line passing through the points (−10, 0) and (−8, 20) can be expressed as y = mx + b. Give the value of b.
weeeeeb [17]

Given are the two points (-10,0) and (-8,20), and equation of the line as y=mx+b.

We can plug the given values in the equation as follows :-

0 = -10m + b .........equation(1)

20 = -8m + b .........equation(2)

Subtracting equation(1) from equation(2)

20 - 0 = (-8m + b) - (-10m + b)

20 = -8m + b + 10m - b

20 = 10m - 8m

20 = 2m

m = 10

Plugging m=10 in the equation(1)

0 = -10(10) + b

0 = -100 + b

b = 100

So final answer is b = 100.

3 0
3 years ago
Read 2 more answers
Any Suggestions or ideas
Verizon [17]
If AB is twice as large as A'B', the scale factor must be 0.5 to get from AB to A'B':

AB = 2 * A'B' \\  \frac{AB}{2} = A'B'
8 0
4 years ago
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