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3 years ago

Does 32.60 round up or round down

1 answer:

3 0

That all depends what place you want it rounded to.

Rounding to the nearest tenth, it becomes 32.6 .
Rounding to the nearest whole number, it becomes, 33 .
Rounding to the nearest ten or higher order of magnitude, it becomes zero.

You might be interested in

Evaluate the expression when a= 4, b= - 2, and c= 7 - -> 5a - 9 (b - c)

ollegr [7]

Answer:

$65$

Step-by-step explanation:

Given the following question:

$5a-9(b-c)$
a = 4
b = 2
c = 7

In order to find the answer, we need to substitute the variables with the numbers given, and then solve using PEMDAS.

$5\times4-9\times(2-7)$
$2-7=-5$
$5\times4-9\times-5$
$5\times4=20$
$20-9\times-5$
$9\times-5=-45$
$20--45$
$20+45=65$
$=65$

Hope this helps.

8 0

2 years ago

Which relation is a function?

Veseljchak [2.6K]

Answer: B

Step-by-step explanation:

because in A it says 2=3 and 2=2 that is not a function each number has to have an outcome of one possible answer if that is true it is a function.

7 0

3 years ago

Please help. It’s due today

vladimir1956 [14]

Answer:

There's nothing there I believe you forgot to add a link just add or create another question and i'll see what I can do :)

Step-by-step explanation:

5 0

2 years ago

Read 2 more answers

If a club charges dues of $200 a year, it will have 50 members. For each $5 it raises its dues, it loses a member. USE AN EQUATI

Vikentia [17]

Answer:

The value is $y = \$ 225$

Step-by-step explanation:

From the question we are told that

The amount charge per year is $k = \$ 200$

The number of members it will have at this amount is $n = 50$

The amount amount increase that will lead to the loss of a single member is $z = \$ 5$

Generally the total amount the club would obtain from its members is mathematically represented as

$I = Amount \ due\ paid * Number \ of members$

Now let x denote the number of member lost

Hence

$I = (k + zx) (n-x )$

=> $I = (200 + 5x) (50-x )$

=> $I = 10000+50x-5x^2$

Thus the number of members that be removed to give the maximum income from dues is obtained by differentiating the above equation and equating it to zero

$\frac{dI}{dx} = 50-10x$