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Sunny_sXe [5.5K]
3 years ago
9

Does 32.60 round up or round down

Mathematics
1 answer:
adelina 88 [10]3 years ago
3 0

That all depends what place you want it rounded to.

Rounding to the nearest tenth, it becomes  32.6 .
Rounding to the nearest whole number, it becomes,  33 .
Rounding to the nearest ten or higher order of magnitude, it becomes zero.

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Which rate is the lowest price?
m_a_m_a [10]

a. 1.15

b. 6.20 divided by 4 = 1.55

c. 5 divided by 4 = 1.25

d. 5.50 divided by 5 = 1.1


D is correct

6 0
3 years ago
Read 2 more answers
Please help me with this one I don’t understand. I need help with #20 thank you!
dimaraw [331]

part A)

we know that for every 1000 ft the temperature drops by 1.3.

so after 1000ft up it went down by 1.3(1)

2000ft up it went down by 1.3(2) or 2.6

3000ft up it went down by 1.3(3) or 3.9

after 10000 up it went down by 1.3(10) or 13.

part B)

well, the current temperature on the ground where the plane is sitting is -2.8°F, after 10000ft it dropped by 13°, so the temperature will just be -2.8 - 13 = -15.8°F.

8 0
3 years ago
A bakery used 38 pounds of flour to make French bread and
fomenos

Answer:

since we are not given the options, I will write down a few equations that represent the number of French bread loaves and bagels:

  • a = number of loaves of French bread
  • b = number of bagels
  • available amount of flour = 38

2a + b ≤ 38

2a ≤ 38 - b

a ≤ (38 - b) / 2

a ≤ 19 - 0.5b

b ≤ 38 - 2a

b ≤ 2(19 - a)

Hopefully one of these equations is one of the choices given to you.

8 0
3 years ago
The perimeter of the polygon above is
Rama09 [41]

Answer:

80 cm

Step-by-step explanation:

5 points in a star, each point has a perimeter of 16,

16 x 5 = 80

or just legit add all the 8's

DONT FORGET TO INCLUDE THE UNITS

4 0
3 years ago
Read 2 more answers
If θ=0rad at t=0s, what is the blade's angular position at t=20s
babunello [35]
The attached figure represents the relation between ω (rpm) and t (seconds)
To find the blade's angular position in radians ⇒ ω will be converted from (rpm) to (rad/s)
              ω = 250 (rpm) = 250 * (2π/60) = (25/3)π    rad/s
              ω = 100 (rpm) = 100 * (2π/60) = (10/3)π    rad/s

and from the figure it is clear that the operation is at constant speed but with variable levels
            ⇒   ω = dθ/dt   ⇒   dθ = ω dt

            ∴    θ = ∫₀²⁰  ω dt  
 
while ω is not fixed from (t = 0) to (t =20)
the integral will divided to 3 integrals as follow;
       ω = 0                                          from t = 0  to t = 5
       ω = 250 (rpm) = (25/3)π            from t = 5   to t = 15
       ω = 100 (rpm) = (10/3)π            from t = 15 to t = 20

∴ θ = ∫₀⁵  (0) dt   + ∫₅¹⁵  (25/3)π dt + ∫₁₅²⁰  (10/3)π dt
     
the first integral = 0
the second integral = (25/3)π t = (25/3)π (15-5) = (250/3)π
the third integral = (10/3)π t = (25/3)π (20-15) = (50/3)π

∴ θ = 0 + (250/3)π + (50/3)π = 100 π

while the complete revolution = 2π
so instantaneously at t = 20
∴ θ = 100 π - 50 * 2 π = 0 rad

Which mean:
the blade will be at zero position making no of revolution = (100π)/(2π) = 50
















3 0
3 years ago
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