I'm assuming that the diagonals intersect at E. Since diagonals of a parallelogram bisect each other, BE=ED.
- 7x-2=x²-10
- x²-7x-8=0
- (x-8)(x+1)=0
- x = -1, 8
As distance must be positive, we reject the negative case, so x=8.
Thus, BE=ED=54.
Answer:
50 degrees
Step-by-step explanation:
Okay! So first off, because this is NOT a right triangle, we can't use soh cah toa. That means we can either use the law of sines or the law of cosines.
Because we only have sides here and no angles, we are forced to use the law of cosines.
c^2 = a^2 + b^2 − 2ab cos(C)
c = 6
b = 7.5
a = 6.5
36 = 6.5^2 + 7.5^2 - 2(6.5)(7.5)cos(C)
36 = 98.5 - 97.5cos(C)
-62.5 = -97.5cos(C)
0.641 = cos(C)
angle C = cos^-1(0.641)
angle C = 50.13 which is around 50 degrees
Remember! A dumb thing i always used to do in geometry was use radians instead of degrees, be sure to use degrees here because you are looking for degrees. Radians are for things involving not degrees, but PI.
Answer:
KI=11.25 and HI=6.75
Step-by-step explanation:
Consider the below figure attached with this question.
According to Pythagoras Theorem:
Use Pythagoras in triangle HKL
Taking square root on both sides.
Let length of HI be x.
LI = 12+x
Use Pythagoras theorem in ΔKLI,
Use Pythagoras theorem in ΔHKI,
From (1) and (2) we get
Hence, the measure of HI is 6.75 units.
Substitute x=6.75 in equation (2).
Taking square root on both sides.
Hence, the measure of KI is 11.25 units.
