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hodyreva [135]
3 years ago
13

For g(x) = 3x, describe the value of x when g(x) < 27. When g(x) < 27, x<

Mathematics
1 answer:
enyata [817]3 years ago
4 0

Answer:

x < 9

if g(x) < 27

Step-by-step explanation:

Since g(x) = 3x

then for g(x) = 27

3x = 27

x = 27/3

x = 9

so when g(x) < 27

x < 9

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Find the common difference if the 8th term is 55 and the first term is 13
Vlad [161]

Answer:

Step-by-step explanation:

Equation

L = a + (n - 1)*d

Givens

L = 55

a = 13

n =8

Solution

55 = 13 + (8 - 1)*d               Combine

55 = 13 + 7d                       Subtract 13 from both sides

55 - 13 = 7d

42 = 7d                               Divide by 7

d = 6

6 0
3 years ago
Gabrielle's age is three times Mikhail's age. The sum of their ages is 84. What is Mikhail's age?
Whitepunk [10]

Answer: 21

Step-by-step explanation:

84 divided by 4 = 21 since grabielle is 21, and then mikhail is gonna be 3 times more so it’s gonna be 63

7 0
3 years ago
Read 2 more answers
Sara has $50 in her wallet in $5 and $20 bills. Create a linear equation (with
77julia77 [94]

Answer:

<em>0 $20 bills and 10 $5 bills</em>

<em>1 $20 bills and 6 $5 bills</em>

<em>2 $20 bills and 2 $5 bills</em>

Step-by-step explanation:

<u>Equations</u>

Let's set:

x=number of $5 bills

y=number of $20 bills

The total amount Sara has is given by

5x+20y

And we know it's equal to $50, thus:

5x+20y=50

Dividing by 5

x+4y=10

We would need another condition to solve for x and y, but we can determine some combinations that solve the problem.

Solving for x:

x=10-4y

Since both x and y are integers and cannot be negative:

10-4y≥0

Swapping sides:

4y≤10

Dividing by 4:

y≤2.5

Thus, y can only have the values {0,1,2}

For y=0

x=10-4*0=10

x=10

For y=1

x=10-4*1=6

x=6

For y=2

x=10-4*2=2

x=2

Thus, the possible combinations are:

0 $20 bills and 10 $5 bills

1 $20 bills and 6 $5 bills

2 $20 bills and 2 $5 bills

4 0
3 years ago
(4,7,12,19) How do you right this in recursive and explicit equations??????? pls help
Soloha48 [4]

You can see how the difference between two consecutive terms is constantly increasing:

a_1 = 4

a_2 = 7 = 4+3

a_3 = 12 = 7+5

a_4 = 19 = 12+7

So, for the next terms we'll have to add +9, +11, +13 and so on.

Also, note that a_2 is obtained by adding the 2nd odd number to a_1, a_3 is obtained by adding the 3rd odd number to a_2, and so on.

So, the recursive formula is

a_n = a_{n-1}+(2n-1),\quad a_1=1

For the explicit formula, recall that the sum of the first n odd numbers is n squared. Taking into account the fact that we're not starting from 1, we have

a_n = n^2+3

7 0
3 years ago
4 (b-6)+19 simplify the expression
BlackZzzverrR [31]
4b - 6b + 19
Answer : -2b + 19
3 0
3 years ago
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