Check the picture below.
since chords NQ and MP cross the center of the circle at R, that means that those two chords are diametrical chords and the angles made by both are vertical angles and thus twin angles, namely both are 18° as you see in the picture, so the angle NMP in magenta is really 162° + 18° + 18° = 198°, and we know the radius NR is 8.
![\textit{arc's length}\\\\ s=\cfrac{r\pi \theta }{180}~~ \begin{cases} r=radius\\ \theta =\stackrel{degrees}{angle}\\[-0.5em] \hrulefill\\ r=8\\ \theta =198 \end{cases}\implies s=\cfrac{(8)\pi (198)}{180}\implies s\approx 27.6](https://tex.z-dn.net/?f=%5Ctextit%7Barc%27s%20length%7D%5C%5C%5C%5C%20s%3D%5Ccfrac%7Br%5Cpi%20%5Ctheta%20%7D%7B180%7D~~%20%5Cbegin%7Bcases%7D%20r%3Dradius%5C%5C%20%5Ctheta%20%3D%5Cstackrel%7Bdegrees%7D%7Bangle%7D%5C%5C%5B-0.5em%5D%20%5Chrulefill%5C%5C%20r%3D8%5C%5C%20%5Ctheta%20%3D198%20%5Cend%7Bcases%7D%5Cimplies%20s%3D%5Ccfrac%7B%288%29%5Cpi%20%28198%29%7D%7B180%7D%5Cimplies%20s%5Capprox%2027.6)
Candies with celias and emmas is 60 and 45 respectively.
<u>Solution:</u>
Given, Getting home from trick or treat celia and emma counted their candies. Half of celias candies is equal to 2/3 of emmas candies.
They had a total of 105 candies altogether.
We have to find how many candies did each of them have.
Let the number of candies with celias be n, then number of candies with emma will be 105 – n.
Now according to given condition.

Hence, candies with celias and emmas is 60 and 45 respectively.
Answer:
Both child tickets and senior tickets cost $14.
Step-by-step explanation:
Since the school that DeShawn goes to is selling tickets to the annual dance competition, and on the first day of ticket sales, the school sold 10 senior citizen tickets and 8 child tickets for a total of $ 252, while the school took in $ 280 on the second day by selling 10 senior citizen tickets and 10 child tickets, to determine what is the price of each of one senior citizen ticket and one child ticket, the following calculation must be performed:
10 senior tickets + 8 child tickets = 252
10 senior tickets + 10 child tickets = 280
280 - 252 = 2 child tickets
28 = 2 child tickets
28/2 = 1 child ticket
14 = 1 child ticket
14 x 10 = 140
(280 - 140) / 10 = senior tickets
140/10 = 14 = senior tickets
Therefore, both child tickets and senior tickets cost $14.
Given that Trent's watch runs at half the speed it should run, this implies that
for every hour passed, his watch moves by half an hour.
Hence, for every half-hour passed, Trent's watch moves by 15 minutes.
Hence, when the real time is 10:30 am, Trent's watch will show 9:15 am.