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nataly862011 [7]
3 years ago
6

Richard has $1,089.26 in his checking account at the end of the month. During the month, he withdrew $120, deposited a check for

$325, and wrote one check for $425 and one check for $24.10. What was his checking account balance at the beginning of the month?
$845.16
$1,093.36
$1,333.36
$1,490.16
Mathematics
1 answer:
kykrilka [37]3 years ago
5 0

Answer:

The first option is the right answer $ 845.16

Step-by-step explanation:

1.089.26-120=969.26

969.26+325=1.294.26

1.294.26-425=869.26

869.26-24.10= 845.16

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Genrish500 [490]

Answer:

The Area = 28.26 or 28.27 depends if you round or not

4 0
2 years ago
Graph the line for <br> y+1=−3/5(x−4)<br> on the coordinate plane.
Naddika [18.5K]
Please enclose that -3/5 in parentheses:  <span>y+1= (−3/5)(x−4)
</span>
Let's use the intercept method to graph this line.
First, set x = 0 and find y; this y will be the y-coordinate of the vertical intercept:

y+1= (−3/5)(0−4)  =>  y = -1 + 12/5 = -5/5 + 12/5 = 7/5.  Plot (0, 7/5).

Next, set y = 0 and find x; this will give us the coordinate of the horiz. int.:

0+1= (−3/5)(x−4) => -5/3 = x - 4, or x = 4- 5/3, or  x = 7/3.  Plot (7/3, 0).

Now draw a straight line thru these two points.

6 0
3 years ago
Read 2 more answers
An elementary ntimesn scaling matrix with k on the diagonal is the same as the ntimesn identity matrix with _______ exactly one
Dafna11 [192]

Answer:

exactly one, 0's, triangular matrix, product and 1.

Step-by-step explanation:

So, let us first fill in the gap in the question below. Note that the capitalized words are the words to be filled in the gap and the ones in brackets too.

"An elementary ntimesn scaling matrix with k on the diagonal is the same as the ntimesn identity matrix with EXACTLY ONE of the (0's) replaced with some number k. This means it is TRIANGULAR MATRIX, and so its determinant is the PRODUCT of its diagonal entries.​ Thus, the determinant of an elementary scaling matrix with k on the diagonal is (1).

Here, one of the zeros in the identity matrix will surely be replaced by one. That is to say, the determinants = 1 × 1 × 1 => 1. Thus, it is a a triangular matrix.

3 0
3 years ago
Help with #7 and #8?
arsen [322]

Answer:

M(6,5) and G(2,9)

Step-by-step explanation:

m = ( \frac{x1 + x2}{2}, \frac{y1 + y2}{2} )

B(3,6)

C(9,4)

m = [(3+9)/2 , (6+4)/2]

= (6,5)

M(5,9)

H(8,9)

G(x,y)

[(x+8)/2 , (y+9)/2]=(5,9)

(x+8)/2 = 5

x+8 = 10

x = 2

(y+9)/2 = 9

y+9 = 18

y = 9

G(2,9)

(Correct me if i am wrong)

5 0
3 years ago
If the point (2,5) is on the graph of an equation, which statement must be
Hunter-Best [27]

Answer: D

Step-by-step explanation:

The values x = 2 and y = 5 make the equation true.

4 0
3 years ago
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