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Brrunno [24]
2 years ago
13

Which of the following is most likely to be a relative maximum for this graph?

Mathematics
2 answers:
SIZIF [17.4K]2 years ago
8 0

The relative maximum for this graph is most likely to be choice A

e-lub [12.9K]2 years ago
7 0

Answer:

A. (-1,8)

Step-by-step explanation:

We know that,

<em>Relative maximum/minimum </em><em>at a point 'c' is obtained by equating the derivative of a function to 0.</em>

<em>As the derivative of a function at a point represents the tangent line at the point which is parallel to x-axis.</em>

So, in order to find the relative maximum, we will find the highest point at which the tangent is parallel to the x-axis.

Since from the graph, we see that,

The point (-1,8) is the highest point such that tangent is parallel to the x-axis.

We get, (-1,8) is the relative maximum point.

Thus, option A is correct.

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Please Help ! Will give brainliest!
sveta [45]

Answer:

D: I and IV only.

Step-by-step explanation:

We can go through each statement and examine its validity.

I) All congruent triangles are similar.

For congruent triangles, all of its corresponding sides and angles are congruent.

Since all angles are congruent, this fulfills the AA Similarity criterion. Thus, I is true.

II) All similar triangles are congruent.

Congruence guarantees similarity, but similarity does not guarantee congruence.

Two triangles need only two congruent angles to guarantee similarity, while two congruent angles does guarantee congruence. II is false.

III) All right triangles are similar.

Triangles are similar through the AA criterion. One angle of a right triangle must be 90, so this leaves 90 for the two remaining angles. Since these two angles can be anything that sum to 90, we are not guaranteed similarity. For example, 20 - 70 - 90 and 30 - 60 - 90 triangles. They are both right triangles, but are not similar. III is false.

IV) All isosceles right triangles are similar.

Again, since we have a right triangle, one angle is 90, which leaves two remaining angles that must sum to 90.

However, since it is isosceles, the two remaining angles must measure the same. Only one solution exists then: both angles must be 45.

Since all angles must be 45 - 45 - 90, it fulfills the AA Criterion. Thus, all isosceles right triangles are similar. IV is true.

The correct statements are I and IV.

3 0
3 years ago
A floor plan shows that a tiny house has a length of 40 feet and a width of 25 feet
Oduvanchick [21]

Answer:

1000 square feet.

Step-by-step explanation:

to find the area, you multiply the length by the width

40*25=1000

3 0
2 years ago
11 less than the product of a number and -4
denpristay [2]

Answer:

-4n - 11

Step-by-step explanation:

Step 1:  Convert words into an expression

11 less than the product of a number and -4

(n * -4) - 11

<em>-4n - 11</em>

<em />

Answer:  -4n - 11

<u>If needed solve</u>

-4n - 11 + 11 = 0 + 11

-4n / -4 = 11 / -4

<em>n = -2.75</em>

7 0
3 years ago
A farm had 480 acres more wheat than corn. After the farmers collected 80% of the wheat and 25% of the corn, the area of the whe
Sergio [31]
The area covered by corn is x
The area covered by wheat is (x+480)
After 80% of wheat was collected, the new area was:
20/10(x+480)
=1/5(x+480)
After 25% of the corn was collected, the new area was:
75/100x
=3/4x
New area equation will be:
(3/4)x=1/5(x+480)+300
(3/4x)=(1/5)x+96+300
solving for x we get:
11/20x=396
x=720
thus the original area of corn was 720 acres
Original area of wheat was 720+480=1200 acres
7 0
3 years ago
<img src="https://tex.z-dn.net/?f=%20%5Cfrac%7Bx%20%7B%7D%5E%7B2%7D%20-%204%20%7D%7B%20%5Csqrt%7Bx%20%7B%7D%5E%7B2%7D%20-%206x%2
Nimfa-mama [501]

First of all, we can observe that

x^2-6x+9 = (x-3)^2

So the expression becomes

\dfrac{x^2-4}{\sqrt{(x-3)^2}} = \dfrac{x^2-4}{|x-3|}

This means that the expression is defined for every x\neq 3

Now, since the denominator is always positive (when it exists), the fraction can only be positive if the denominator is also positive: we must ask

x^2-4 \geq 0 \iff x\leq -2 \lor x\geq 2

Since we can't accept 3 as an answer, the actual solution set is

(-\infty,-2] \cup [2,3) \cup (3,\infty)

7 0
2 years ago
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