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ser-zykov [4K]
3 years ago
9

6d2+8d-5=0

Formula1" title="6d {}^{2} + 8d - 5 = 0 \\ " alt="6d {}^{2} + 8d - 5 = 0 \\ " align="absmiddle" class="latex-formula">
Mathematics
1 answer:
FromTheMoon [43]3 years ago
5 0
The answer is d= 1/4
hope this helps
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Pls, help me work this out!
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It would be 3 lbs apple because your are dividing
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1 year ago
, use a number line. Start at 0. Move forward 5 and then back up 7. How many yards must he get to get back to 0?
krek1111 [17]

Answer:

2 yards.

Step-by-step explanation:

If you do what was stated in the problem, you would be left at -2. So, you would need to move up 2 yards to get back to 0.

8 0
3 years ago
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Estimate the sum <br><br> 1.37 + 0.9
guajiro [1.7K]

1.37 + 0.9\\\\\\=\dfrac{137}{100} + \dfrac{9}{10}\\\\\\=\dfrac{137}{100}+\dfrac{90}{100}\\\\\\=\dfrac{137+90}{100}\\\\\\=\dfrac{227}{100}\\\\\\=2.27

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2 years ago
A brick is thrown upward from the top of a building at an angle of 250 above the horizontal, and with an initial speed of 15 m/s
mojhsa [17]

Answer:

(a) 25.08 m

(b) 2.05 m

Step-by-step explanation:

Let the height of the building be 'h'.

Given:

Angle of projection is, \theta=25°

Initial speed is, u=15\ m/s

Time of flight is, t=3.0\ s

(a)

Consider the vertical motion of the brick.

Vertical component of initial velocity is given as:

u_y=u\sin\theta\\\\u_y=15\sin(25)=6.34\ m/s

Vertical displacement of the brick is equal to the height of the building.

So, vertical displacement = -h (Negative sign implies downward motion)

Acceleration is due to gravity in the downward direction. So,

Acceleration is, g=-9.8\ m/s^2

Now, using the following equation of motion;

-h=u_yt+\frac{1}{2}gt^2\\-h=6.34(3)-\frac{9.8}{2}(3)^2\\\\-h=19.02-44.1\\\\-h=-25.08\\\\h=25.08\ m

Therefore, the building is 25.08 m tall.

(b)

Let the maximum height be 'H'.

At maximum height, the vertical component of velocity is 0 as the brick stops temporarily in the vertical direction.

So, v_y=0\ m/s

Now, using the following equation of motion, we have:

v_y^2=u_y^2+2gH\\\\0=(6.34)^2-2\times 9.8\times H\\\\19.6H=40.2\\\\H=\frac{40.2}{19.6}=2.05\ m

Therefore, the maximum height of the brick is 2.05 m.

5 0
3 years ago
Find the coordinates of the midpoint of RS if R(-8,-3) and S(2,7) (-3,-2) (2,-3) (3,-2) (-3,2)
Tanzania [10]

Answer:

Step-by-step explanation:

(-8+2)/2= -6/2 = -3

(-3+7)/2= 4/2 = 2

(-3, 2) midpoint

4 0
3 years ago
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