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loris [4]
2 years ago
6

Identify the coefficient in the term 7x^2y^3

Mathematics
1 answer:
Advocard [28]2 years ago
3 0

Answer:

<h3>LARGEST COEFFICIENT = 7</h3><h3>SMALLEST COEFFICIENT=2</h3><h3>STANDARD FORM=7,0,0,0,3,2,0,0</h3><h3>COEFFICIENTS =7,3,2</h3>
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Morton made 36 out of 48 free throws last season. What percent of his free throw did Morton make?
sveta [45]
Just divide 36 by 48, and you will get that he made 75% of his free throws.
8 0
3 years ago
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Flying against the wind, an airplane travels 7520 kilometers in 8 hours. Flying with the wind, the same plane travels 6500 kilom
bezimeni [28]

Answer:

Rate of plane in still air = 1120 km/h

Rate of wind = 180 km/h

Step-by-step explanation:

Let the rate (speed) of the plane in still air = u km/h

Let the rate (speed) of the wind = v km/h

Formula for speed is:

Speed = \dfrac{Distance}{Time}

Given that against the wind, airplane travels 7520 km in 8 hours.

The speed against the wind will be slower so,

Against the wind, speed = (u -v ) km/h

Using above formula:

(u-v) = \dfrac{7520}{8} km/h\\(u-v) = 940 km/h ..... (1)

Given that with the wind, airplane travels 6500 km in 5 hours.

The speed with the wind will be faster so,

With the wind, speed = (u +v ) km/h

Using above formula:

(u+v) = \dfrac{6520}{5} km/h\\(u+v) = 1300 km/h ..... (2)

Adding (1) and (2) to solve for u and v:

2u = 2240\\\Rightarrow u = 1120\ km/h

Putting u in (1):

1120-u=940\\\Rightarrow u = 180\ km/h

So, the answers are:

<em>Rate of plane in still air = 1120 km/h</em>

<em>Rate of wind = 180 km/h</em>

<em></em>

6 0
3 years ago
Help plz I need help
zalisa [80]

Answer:

D. 240

Step-by-step explanation:

We have 20 stamps in 1 book.

We are give 12 books.

20(12) = 240

5 0
3 years ago
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M is the midpoint of CF for the points c(3,7) and f(5,5). Find MF
Marizza181 [45]
(4,6), Using the midpoint formula which is (( x1 + x2)/2), ((y1+y2)/2)
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2 years ago
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Solve for x <br> -3(-5x+2)+x-3=39
omeli [17]
15x-6+x-3=39
16x-9=39
16x=39+9
16x=48
x=48/16
x=3
4 0
3 years ago
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