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Alenkasestr [34]
3 years ago
7

A full grain silo empties at a constant rate. Write an expression to determine the amount after 5 seconds and make sure to be pr

ecise! Someone please help me! I need an answer fast! ;-;
Mathematics
1 answer:
Artist 52 [7]3 years ago
7 0
What is the constant rate
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What is the diameter of a circle with circumference<br> C= 191 ? Leave answers in exact form.
lesantik [10]

Answer:

Diameter=60.79

Step-by-step explanation:

Solution,\\ Circumference(C)=191\\As,\\Circumference=\pi d\\191=\pi d\\\frac{191}{\pi } =d\\d=60.79718826

8 0
3 years ago
This is the same question as last time just not blurry.
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3 years ago
Read 2 more answers
Some scientists believe alcoholism is linked to social isolation. One measure of social isolation is marital status. A study of
frez [133]

Answer:

1) H0: There is independence between the marital status and the diagnostic of alcoholic

H1: There is association between the marital status and the diagnostic of alcoholic

2) The statistic to check the hypothesis is given by:

\sum_{i=1}^n \frac{(O_i -E_i)^2}{E_i}

3) \chi^2 = \frac{(21-33.143)^2}{33.143}+\frac{(37-41.429)^2}{41.429}+\frac{(58-41.429)^2}{41.429}+\frac{(59-46.857)^2}{46.857}+\frac{(63-58.571)^2}{58.571}+\frac{(42-58.571)^2}{58.571} =19.72

4) df=(rows-1)(cols-1)=(3-1)(2-1)=2

And we can calculate the p value given by:

p_v = P(\chi^2_{2} >19.72)=5.22x10^{-5}

And we can find the p value using the following excel code:

"=1-CHISQ.DIST(19.72,2,TRUE)"

Since the p value is lower than the significance level so then we can reject the null hypothesis at 5% of significance, and we can conclude that we have association between the two variables analyzed.

Step-by-step explanation:

A chi-square goodness of fit test "determines if a sample data matches a population".

A chi-square test for independence "compares two variables in a contingency table to see if they are related. In a more general sense, it tests to see whether distributions of categorical variables differ from each another".

Assume the following dataset:

                    Diag. Alcoholic   Undiagnosed Alcoholic    Not alcoholic    Total

Married                     21                              37                            58                116

Not Married              59                             63                            42                164

Total                          80                             100                          100              280

Part 1

We need to conduct a chi square test in order to check the following hypothesis:

H0: There is independence between the marital status and the diagnostic of alcoholic

H1: There is association between the marital status and the diagnostic of alcoholic

The level os significance assumed for this case is \alpha=0.05

Part 2

The statistic to check the hypothesis is given by:

\sum_{i=1}^n \frac{(O_i -E_i)^2}{E_i}

Part 3

The table given represent the observed values, we just need to calculate the expected values with the following formula E_i = \frac{total col * total row}{grand total}

And the calculations are given by:

E_{1} =\frac{80*116}{280}=33.143

E_{2} =\frac{100*116}{280}=41.429

E_{3} =\frac{100*116}{280}=41.429

E_{4} =\frac{80*164}{280}=46.857

E_{5} =\frac{100*164}{280}=58.571

E_{6} =\frac{100*164}{280}=58.571

And the expected values are given by:

                    Diag. Alcoholic   Undiagnosed Alcoholic    Not alcoholic    Total

Married             33.143                       41.429                        41.429                116

Not Married     46.857                      58.571                        58.571                164

Total                   80                              100                             100                 280

And now we can calculate the statistic:

\chi^2 = \frac{(21-33.143)^2}{33.143}+\frac{(37-41.429)^2}{41.429}+\frac{(58-41.429)^2}{41.429}+\frac{(59-46.857)^2}{46.857}+\frac{(63-58.571)^2}{58.571}+\frac{(42-58.571)^2}{58.571} =19.72

Part 4

Now we can calculate the degrees of freedom for the statistic given by:

df=(rows-1)(cols-1)=(3-1)(2-1)=2

And we can calculate the p value given by:

p_v = P(\chi^2_{2} >19.72)=5.22x10^{-5}

And we can find the p value using the following excel code:

"=1-CHISQ.DIST(19.72,2,TRUE)"

Since the p value is lower than the significance level so then we can reject the null hypothesis at 5% of significance, and we can conclude that we have association between the two variables analyzed.

7 0
4 years ago
Determine the y intercept for the following equation y=2x-8
Orlov [11]

Answer: The y-intercept is -8

Step-by-step explanation:

It's simple to understand once you memorize the slope intercept formula!

y=mx+b

m stands for the slope which is rise/run

The b is the y-intercept, which is the answer you are looking for! the y-intercept is where the line crosses the y-axis!

3 0
3 years ago
Find the interest rate r compounded monthly if the principal P = $4,300 reaches the future value F = $4,720 in t = 6 years. Roun
kirza4 [7]

Answer:

  1.55%

Step-by-step explanation:

Fill in the values and solve for the rate using the future value formula.

  FV = P(1 +r/n)^(nt)

  4720 = 4300(1 +r/12)^(12·6)

  (4720/4300)^(1/72) = 1 +r/12

  r = 12(4720/4300)^(1/72) -1) ≈ 0.015542

The annual interest rate is about 1.55%.

4 0
3 years ago
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