Help with math again please

Corner Grocery charges $4.80 for 12 sodas. Max's Market charges $5.25 for 15 sodas.

weeeeeb [17]

Answer:

To do this, just do 12 divided by 4.80 = 2.5 dollars per can at Corner Grocery, and at Max's Market 15 divided by 5.25 = 2.85 per can. So the Corner Grocery has a better unit price by 35 cents.

Thanks for your question.

8 0

3 years ago

Given segment AC and point B that lies on AC,

ololo11 [35]

The total length of the segment AC is the sum of AB and CB, which gives, CB = 9

<h3>How can the length of CB be found?</h3>

The given parameters are;

AC = 17
AB = 32 + 3•x
CB = 57 + 6•x

Required: <em>CB</em>

Solution:

AC = <em>AB + CB</em> by segment addition property

Therefore;

AC = 17 = 32 + 3•x + 57 + 6•x = 89 + 9•x

17 = 89 + 9•x

$x = \frac{17 - 89}{9} = - 8$

CB = 57 + 6•x = 57 + 6 × (-8) = 9

Therefore;

<u>CB = 9</u>

Learn more about segment addition postulate here: brainly.com/question/1721582

#SPJ1

8 0

2 years ago

In right triangle ABC, ∠B is a right angle and AB=72, BC=65, and AC=97.

notsponge [240]

Answer:

sinC=56/72

Step-by-step explanation: I cant explain it but it’correct

4 0

3 years ago

The perimeter of a triangular field is 120m. Two of the sides are 21m and 40m.Calculate the largest angle of the field.

Mama L [17]

Answer:

the largest angle of the field is 149⁰

Step-by-step explanation:

Given;

perimeter of the triangular filed, P = 120 m

length of two known sides, a and b = 21 m and 40 m respectively

The length of the third side is calculated as follows;

a + b + c = P

21 m + 40 m + c = 120 m

61 m + c = 120 m

c = 120 m - 61 m

c = 59 m

B

↓ ↓

A → → → → → → → → → → → C

Consider ABC as the triangular field;

Angle A is calculated by applying cosine rule;

$a^2 = b^2 + c^2 - 2bc \ Cos A\\\\Cos \ A = \frac{b^2 + c^2 - a^2}{2bc} \\\\Cos \ A = \frac{40^2 + 59^2 - 21^2}{2 \times 40 \times 59} \\\\Cos \ A = 0.983\\\\A = Cos ^{-1} (0.983)\\\\A = 10.6 \ ^0$

Angle B is calculated as follows;

$Cos \ B = \frac{a^2 + c^2 - b^2}{2ac} \\\\Cos \ B = \frac{21^2 + 59^2 - 40^2}{2 \times 21 \times 59} \\\\Cos \ B = 0.937\\\\B= Cos ^{-1} (0.937)\\\\B = 20.5 \ ^0$

Angle C is calculated as follows;

$Cos \ C = \frac{a^2 + b^2 - c^2}{2ab} \\\\Cos \ C = \frac{21^2 + 40^2 - 59^2}{2 \times 21 \times 40} \\\\Cos \ C = -0.857\\\\C = Cos ^{-1} (-0.857)\\\\C = 149\ ^0$

Therefore, the largest angle of the field is 149⁰.

8 0

3 years ago

PLEASE HELP 35 POINTS!!!

lawyer [7]

Answer:

circle = square =5.53

Step-by-step explanation: .

6 0

3 years ago