A right triangle can be considered as a special type
because the relationship of its sides can be described using the hypotenuse
formula:
c^2 = a^2 + b^2
or
c^2 = x^2 + y^2
where,
c is the hypotenuse of the triangle and is the side
opposite to the 90° angle
while a and b are the sides adjacent to the 90° angle
In the problem statement, we are given that one of the
side has a measure of 2 = x, while the hypotenuse is 5 = c, therefore calculating
for y:
y^2 = c^2 – x^2
y^2 = 5^2 – 2^2
y^2 = 21
y = 4.58
The natural number is the number before the decimal.
Therefore the answer is:
y = 4
(1,11/4)(2,25/4)
slope = (25/4 - 11/4) / (2 - 1) = (14/4) / 1 = 14/4 = 7/2
y = mx + b
slope(m) = 7/2
(1,11/4)...x = 1 and y = 11/4
now we sub and find b, the y int
11/4 = 7/2(1) + b
11/4 = 7/2 + b
11/4 - 7/2 = b
11/4 - 14/4 = b
-3/4 = b
so ur equation is : y = 7/2x - 3/4
Answer:
y = -2x - 3
Step-by-step explanation:
Answer:
Graph A: y = (1/2)x - 2
Step-by-step explanation:
2x−4y=8 in slope-intercept form is -4y = -2x + 8, or y = 1/2x - 2
The slope of this line is 1/4 and the y-intercept is -2. This is represented by Graph A.
Answer:
1.2 cm
Step-by-step explanation:
The area of sircumscribed quadrilateral over a circle is equal to
where s is semi-perimeter of the quadrilateral and r is the radius of the circle.
Use property of circumscribed quadrilateral: The sums of the opposite sides are equal.
So, if the sum of two opposite sides of the circumscribed quadrilateral is 10 cm, then the sum of another two sides is also 10 cm and the perimeter of the quadrilateral is 20 cm. Hence,
Now,
