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guajiro [1.7K]
3 years ago
14

Help ASAP Both please

Mathematics
1 answer:
mars1129 [50]3 years ago
5 0

It doesn't matter what number the negative sign is on. What matters is if the negative sign is there at all.

1) A & B

2) C & D


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Find a quadratic equation with roots -1, 4i and -1 - 4i
vazorg [7]
\bf \textit{difference of squares}
\\\\
(a-b)(a+b) = a^2-b^2\qquad \qquad 
a^2-b^2 = (a-b)(a+b)
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\textit{also recall that }i^2=-1\\\\
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\begin{cases}
x=-1+4i\implies &x+1-4i=0\\
x=-1-4i\implies &x+1+4i=0
\end{cases}
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(x+1-4i)(x+1+4i)=\stackrel{y}{0}
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[(x+1)~~-~~(4i)][(x+1)~~+~~(4i)]=y
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[(x+1)^2~~-~~(4i)^2]=0\implies (x^2+2x+1)~-~(4^2i^2)=y
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(x^2+2x+1)~-~(16\cdot -1)=y\implies (x^2+2x+1)~-~(-16)=y
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x^2+2x+1~~+16=y\implies x^2+2x+17=y
3 0
3 years ago
Write a third degree polynomial function that has real zeros -1, -2 and 4
ra1l [238]

Answer:

f(x) = x^{3}  - x^{2}  -  10x  -8

Step-by-step explanation:

All you have to do is multiply (x + 1)(x + 2)(x - 4)

You should get x^{3}  - x^{2}  -  10x  -8

So,  f(x) = x^{3}  - x^{2}  -  10x  -8

8 0
3 years ago
Find the perimeter of the figure to the nearest hundredth.
babunello [35]

Answer:

50.28 inches

Step-by-step explanation:

From the Image, we can find the length of the arc of the semi-circle by dividing the circumference of the resulting circle by 2

Radius= 9in

C= 2πr

C=2*3.142*9

C=2*3.142*9

C= 56.556 inches

Hence the length of the arc is

=56.556/2

=28.278 inches

The perimeter of the shape

=28.278+5+12+5

=50.28 inches

8 0
3 years ago
the diagram gives the dimensions of a swimming pool.if a cover is needee for the pool, what will be the approximate area of the
mars1129 [50]
The answer is 360 because if u do this 20×36 and the 1/2 it u get this 360 20×36 is 720 and then 2÷720 u get 360
7 0
3 years ago
Show all of your work. Simplify the expression: 4(3x + 2) + 5x​
Kamila [148]

Answer:

17x + 8

Step-by-step explanation:

4(3x + 2) + 5x​

12x + 8 + 5x

17x + 8

8 0
3 years ago
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