NASA launches a rocket at t = 0 seconds. Its height, in meters above sea-level, as a function of time is given by
The sea level is represented by h = 0, therefore, to find the corresponding time when h splashes into the ocean we have to solve for t the following equation:
Using the quadratic formula, the solution for our problem is
The rocket splashes after 26.845 seconds.
The maximum of this function happens at the root of the derivative. Differentiating our function, we have
The root is
Then, the maximum height is
1029.99 meters above sea level.
we'd do the same as before on this one as well.
if we take 27.99 to be the 100%, what is 12 off of it in percentage?
Given:
The increase in pressure P is the linear function of the depth d.
The cost of dinner is $300 and $10 per students.
To find:
The initial value and rate of change and their interpretation.
Find the cost function C where n is the number of students.
Solution:
The slope intercept form of a linear function is
...(i)
where, m is rate of change and b is y-intercept or initial value.
We have,
...(ii)
From (i) and (ii), we get
The initial value is 14.7. It means, the pressure at sea level is 14.7 pounds psi.
Rate of change is 0.445. It means, the pressure is increasing by 0.445 pounds psi for every feet.
The cost of dinner is $300 and $10 per students.
Let C(n) be the total cost for dinner and n be the number of students.
Fixed cost = $300
Additional cost for 1 student = $10
Additional cost for n student = $10n
Now,
Total cost = Fixed cost + Additional cost
Therefore, the required cost function is .
Answer:
P = 1/3
P = 0.333
Step-by-step explanation:
There are 6 marbles in the pack, two of them are yellow.
Hope this helps
Its about 13.64% multiply 4.75 by 100 then divide by 5.5 then subtract that number from 100
