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3 years ago

8

Candy is on sell for $0.75 each. You have a coupon for $.25 off your total purchase. Write a function rule for the cost of n pie

ces of candy

2 answers:

weeeeeb [17]3 years ago

8 0

Answer:

.75 -.25=n

Step-by-step explanation:

.75 -.25=n

enyata [817]3 years ago

6 0

t(n)=.75n-.25

Term number x .75 subtract .25

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Use Stokes' Theorem to evaluate C F · dr F(x, y, z) = xyi + yzj + zxk, C is the boundary of the part of the paraboloid z = 1 − x

Serggg [28]

I assume $C$ has counterclockwise orientation when viewed from above.

By Stokes' theorem,

$\displaystyle\int_C\vec F\cdot\mathrm d\vec r=\iint_S(\nabla\times\vec F)\cdot\mathrm d\vec S$

so we first compute the curl:

$\vec F(x,y,z)=xy\,\vec\imath+yz\,\vec\jmath+xz\,\vec k$

$\implies\nabla\times\vec F(x,y,z)=-y\,\vec\imath-z\,\vec\jmath-x\,\vec k$

Then parameterize $S$ by

$\vec r(u,v)=\cos u\sin v\,\vec\imath+\sin u\sin v\,\vec\jmath+\cos^2v\,\vec k$

where the $z$ -component is obtained from

$1-(\cos u\sin v)^2-(\sin u\sin v)^2=1-\sin^2v=\cos^2v$

with $0\le u\le\dfrac\pi2$ and $0\le v\le\dfrac\pi2$ .

Take the normal vector to $S$ to be

$\vec r_v\times\vec r_u=2\cos u\cos v\sin^2v\,\vec\imath+\sin u\sin v\sin(2v)\,\vec\jmath+\cos v\sin v\,\vec k$

Then the line integral is equal in value to the surface integral,

$\displaystyle\iint_S(\nabla\times\vec F)\cdot\mathrm d\vec S$

$=\displaystyle\int_0^{\pi/2}\int_0^{\pi/2}(-\sin u\sin v\,\vec\imath-\cos^2v\,\vec\jmath-\cos u\sin v\,\vec k)\cdot(\vec r_v\times\vec r_u)\,\mathrm du\,\mathrm dv$

$=\displaystyle-\int_0^{\pi/2}\int_0^{\pi/2}\cos v\sin^2v(\cos u+2\cos^2v\sin u+\sin(2u)\sin v)\,\mathrm du\,\mathrm dv=\boxed{-\frac{17}{20}}$

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3 years ago

What is the slope of this line?

Anvisha [2.4K]

(-4,5),(0,6)

slope = rise/run
tip... you have to crawl (run) before you run (rise) .

you can use the slope formula
$\frac{5 - 6}{ - 4 - 0} = \frac{ - 1}{ - 4} = \frac{1}{4}$
1/4

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3 years ago

Look at the box-and-whisker plot.

Marizza181 [45]

i would say B

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3 0

3 years ago

Kim solved the equation below by graphing a system of equations. log base 2 (3x-1) = log base 4 (x+8)

kompoz [17]

Answer:

solution is

$x=1.353,y=1.613$

Step-by-step explanation:

We are given equation as

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First equation is

$y=log_2(3x-1)$

Second equation is

$y=log_4(x+8)$

now, we can draw graph

and then we can find intersection point

we can see that

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so, solution is

$x=1.353,y=1.613$

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3 years ago

Read 2 more answers

I need help on this question

schepotkina [342]

Answer:

0 4 9 1

_____________

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− 0

9 3

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1 7 2

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1 9

− 1 9

0

Step-by-step explanation:

Sorry of this isn't clear

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3 years ago