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ddd [48]
3 years ago
5

At which value in the domain does f(x)=0

Mathematics
2 answers:
amid [387]3 years ago
7 0

Answer:

C

Step-by-step explanation:

f(x)=0 at points of intersection of the graph of the function with x-axis.

From the diagram you can see that the graph of the function intersects x-axis at three points:

  • somewhere between -3 and -2;
  • somewhere between -1 and 0;
  • at x=1.

Since x=1 is the value of x from the domain, then correct choice is option C.

irinina [24]3 years ago
6 0

Answer:

When x equals 1. To solve this, just find the x-intercepts, or where the function intersects the x-axis.

Hope this helps!

Step-by-step explanation:


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liubo4ka [24]

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5 0
3 years ago
Please Help Quicly The equation 8x - 4y = 5 is dilated by a scale factor of 8 centered at the origin. What is the new slope and
Rzqust [24]

For new line, slope m=2 and y-intercept c=(-10)

Step-by-step explanation:

<em>Note : Figure given is for reference to understand better.</em>

<em>Where redline is for given line and blueline for new line</em>

<em />

The equation of given line 8x-4y=5 and it is dilated by a scale factor of 8 centered at the origin.

Step 1 : Find two points on given line.

When x=0, y=?

8x-4y=5

8(0)-4y=5

y=\frac{-5}{4}

When y=0, x=?

8x-4y=5

8x-4(0)=5

x=\frac{5}{8}

We get points A(0,\frac{-5}{4}), B(\frac{5}{8},0)

Step 2: Find distance from centered and scale it.

Now, It is said that line 8x-4y=5 dilated by a scale factor of 8 centered at the origin and point A and point B is on same.

So that point A and point B  will also get dilated by a scale factor of 8 centered at the origin or distance of points from origin will be scaled by 8.

For point A:

Distance of point A(0,\frac{-5}{4}) from origin is ( \frac{-5}{4})  unit in x-direction and zero \frac{-5}{4})  unit in y-direction.

After scaled by factor of 8, the distance will multipy by 8 and new location is A'(0,-10)

For point B:

Distance of point B(\frac{5}{8},0) from origin is (\frac{5}{8}) unit in x-direction and zero unit in y-direction.

After scaled by factor of 8, the distance will multipy by 8 and new location is B'(5,0)

Step 3: Find Equation of new line.

Points A'(0,-10) and B'(5,0) make a new line

The equation of given as

\frac{y-Y1}{x-X1} = \frac{Y2-Y1}{X2-X1}

\frac{y-(-10)}{x-0} = \frac{0-(-10)}{5-0}

\frac{y+(10)}{x} = 2

\frac{y+(10)}{x} = 2

y+10= 2x

y= 2x-10

Now, Comparing with the equation of the line : y=mx + c

Where m=slope and c is the y-intercept

We get, Slope m=2 and y-intercept c=(-10)

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3 years ago
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Answer:

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If BC=2x-3 and AC=2x+10, find the length of AB
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Step-by-step explanation:

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Question 14 of 25
Naily [24]

Answer:

A

Step-by-step explanation:

perpendicular lines are the negative reciprocals of each other, and a pair of these lines intersects at 90 degrees.

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