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Vesna [10]
3 years ago
10

The diagonals of quadrilateral ABCD intersect at point E, AE=5x-10,EC=2x+5, and BE= y/3.. If ABCD is a square, find the value of

y. A. 5 B. 15 C. 30 D. 45

Mathematics
2 answers:
enot [183]3 years ago
5 0
Check the picture below.

Lostsunrise [7]3 years ago
3 0

Answer:

Step-by-step explanation:

Alright, lets get started.

Please refer the diagram I have attached.

As we are given, quadrilateral ABCD is square.

Means its diagonals will intersect each other at their mid point.

So,  AE =EC

5x-10=2x+5

5x-2x= 5+10

3x = 15

x = 5

It means AE = 5x-10 = 5(5)-10 = 25-10=15

AE = BE

So,

\frac{y}{3} = 15

y = 45

hence answer is 45.   :   Answer

Hope it will help :)

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ioda

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203 feet.

Step-by-step explanation:

Please find the attachment.

Let h represent the height of the building.

We have been given that at 3:30 in the afternoon in mid-September the Kimball Tower casts a shadow about 290 feet long when the sun's rays come down at an angle about 35 degrees above the horizontal.    

We know that tangent relates opposite side of a right triangle to its adjacent side.

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Upon substituting our given values in above formula, we will get:

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290*\text{tan}(35^{\circ})=\frac{h}{290}*290

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h=290*0.70020753821

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Therefore, the building is approximately 203 feet high.

 

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