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3 years ago

Which expression is the lcd of these fractions? 9/m^4 and 1/2

Mathematics

1 answer:

I am Lyosha [343]3 years ago

8 0

Least common denom
look at denoms (bottom)

m^4 and 2
LCD is 2m^4
tada

18/(2m^4) and (m^4)/(2m^4)

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I need help please. Thank you! :)

Rudiy27

Answer:

12 for the first one and twelve for the second one

Step-by-step explanation:

i think you can divide for the first one and second one if you divide 240÷20 you will get twelve and if you divide 180÷15 you will get 12

7 0

3 years ago

Find a and b if the points p(6,0) and q(3,2) lie on the graph of ax + by =12

s2008m [1.1K]

Answer:

$a= 2$

$b = 3$

Step-by-step explanation:

Given

$p(x,y) = (6,0)$

$q(x,y) = (3,2)$

$ax + by = 12$

Required

Find a and b

In $p(x,y) = (6,0)$ , $x = 6$ and $y = 0.$

This gives:

$a*6 + b*0 = 12$

$6a = 12$

Divide by 6

$a= 2$

In $q(x,y) = (3,2)$ . $x = 3$ and $y = 2.$

This gives:

$a*3 + b*2 = 12$

$3a + 2b = 12$

Substitute 2 for a

$3*2 + 2b = 12$

$6 + 2b = 12$

Collect Like Terms

$2b = 12 - 6$

$2b = 6$

Divide by 2

$b = 3$

7 0

3 years ago

How are secants related to chords

Fofino [41]

Dear Gaby,
Well I would Say that Any line that intersects a given circle at two different points is called a SECANT and part of secant intercepted between these points is called CHORD of a circle. So basically, Both are very same. ... A Chord connects two points on the circumference of a circle. I hope I could help you my friend and Keep on Rockin'

 Wishing you some Rockin' Answers,
 Mangle

4 0

3 years ago

A recent study focused on the number of times men and women send a Twitter message in a day. The information is summarized below

jok3333 [9.3K]

Answer:

The value of the test statistic = 2.58

Test statistic Z = - 4.805

|Z| = 4.805 > 2.58

Null hypothesis is rejected The value of the test statistic = 2.58

There is significant difference between in the mean number of times men and women send a Twitter message in a day

Step-by-step explanation:

Step(i):-

Sample size of men n₁ = 25

mean of the first sample x₁⁻ = 20

Standard deviation of the first sample σ₁ = 5

Sample size of women n₂ = 30

mean of the second sample x₂⁻ = 30

Standard deviation of the first sample σ₂ = 10

Level of significance ∝= 0.01

Step(ii):-

Null Hypothesis : H₀: There is no significant difference between in the mean number of times men and women send a Twitter message in a day

Alternative Hypothesis :H₁:There is significant difference between in the mean number of times men and women send a Twitter message in a day

Test statistic

$Z = \frac{x^{-} _{1} - x^{-} _{2} }{\sqrt{\frac{S.D_{1} ^{2} }{n_{1} }+\frac{ S.D_{2} ^{2}}{n_{2} } } }$

$Z = \frac{20 - 30 }{\sqrt{\frac{(5)^{2} }{25 }+\frac{ (10)^{2} }{ 30} } }$

Z = $\frac{-10}{2.081} = - 4.805$

The value of the test statistic = 2.58 C

|Z| = 4.805 > 2.58

Null hypothesis is rejected The value of the test statistic = 2.58

Conclusion:-

There is significant difference between in the mean number of times men and women send a Twitter message in a day

7 0

3 years ago

Use the following problem to answer the question below:

kap26 [50]

According to the probles represented above, there is addition of two angles which makes it totally clear. I am pretty sure that the answer with the actual reason of this task is the second option B. Angle Addition Postulate, as you can see a couple of new angles in there :)
Regards!

6 0

3 years ago