Question

A 63 gram piece of magnesium absorbs 6689 joules of heat. The final temperature is 663 degrees Celsius. What was the initial temperature? ( the specific heat of magnesium is 1.023 j/g degrees Celsius)

Answer 1

Answer:

$559^{\circ}C$

Explanation:

When heat is supplied to a substance, the temperature of the substance increases according to:

$Q=m C (T_f-T_i)$

where

Q is the amount of heat supplied

m is the mass of the substance

C is the specific heat capacity of the substance

$T_i$ is the initial temperature

$T_f$ is the final temperature

For the sample of magnesium in this problem, we have:

m = 63 g is the mass

Q = 6689 J is the hear supplied

C = 1.023 J/gC is the specific heat capacity

$T_f=663^{\circ}C$ is the final temperature

Solving the formula for $T_i$, we find the final temperature:

$T_i = T_f-\frac{Q}{mC}=663-\frac{6689}{(63)(1.023)}=559^{\circ}C$