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3 years ago

How does energy move though materials ? (Give a good answer please)

Chemistry

1 answer:

Artyom0805 [142]3 years ago

6 0

Answer:

One way can be with a conductor(metals items yk)

Explanation:

"metal is a better conductor than wood or plastic. Convection is the movement of heat by a fluid such as water or air."

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How much hcl must be added to a liter of buffer that is 1. 5 m in acetic acid and 0. 70 m in sodium acetate to result in a buffe

yaroslaw [1]

For a liter of a buffer that is 1. 5 m in acetic acid and 0. 70 m in sodium acetate, and with a result in a buffer pH of 4.01, the moles of HCl required is mathematically given as x=0.313mol

<h3>What is the result in a buffer ph of 4. 01?</h3>

Generally, the equation for the pH is mathematically given as

pH=pKa+logsalt/acid

Generally, the equation for the Chemical Reaction is mathematically given as

HCl+CH3CooNa---->NaCl+CH3OOH

Therefore

4.01=4.74+log\frac{0.8-x}{1.3+x}

-0.52=log\frac{0.8-x}{1.3+x}

x=0.313mol

In conclusion, The moles of HCl required is

x=0.313mol

Read more about Chemical Reaction

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8 0

2 years ago

What is the mass of oxygen in 1 mole of NaHCO3?

Serga [27]

Answer:

48.00

Explanation:

3 oxygen (15.99 x 3)= 48

3 0

3 years ago

If 1.00 mol of argon is placed in a 0.500-L container at 27.0 degree C , what is the difference between the ideal pressure (as p

ElenaW [278]

Answer:

2.0 atm is the difference between the ideal pressure and the real pressure.

Explanation:

If 1.00 mole of argon is placed in a 0.500-L container at 27.0 °C

Moles of argon = n = 1.00 mol

Volume of the container,V = 0.500 L

Ideal pressure of the gas = P

Temperature of the gas,T = 27 °C = 300.15 K[/tex]

Using ideal gas equation:

$PV=nRT$

$P=\frac{1.00 mol\times 0.0821 L atm/mol K\times 300.15 K}{0.500 L}=49.28 atm$

Vander wall's of equation of gases:

The real pressure of the gas= $p_v$

For argon:

$a=1.345 L^2 atm/mol^2$

b=0.03219 L/mol.

$(p_v+(\frac{an^2}{V^2})(V-nb)=nRT$

$(p_v+(\frac{(1.345 L^2 atm/mol^2)\times (1.00 mol)^2}{(0.500 L)^2})(0.500 L-1.00 mol\times 0.03219L/mol)=1.00 mol\times 0.0821 L atm/mol K\times 300.15 K$