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Schach [20]
3 years ago
13

Choose the option that best answers the question.The points A(0, 0), B(0, 4a – 5) and C(2a + 1, 2a + 6) form a triangle. If Angl

e ABC = 90, what is the area of triangle ABC? 102 120 132 144 156
Mathematics
1 answer:
Sunny_sXe [5.5K]3 years ago
6 0

Answer:

The correct option is 1.

Step-by-step explanation:

Given information: The coordinates of a right angled triangle ABC are A(0, 0), B(0, 4a – 5) and C(2a + 1, 2a + 6). Angle ABC = 90°.

It means AB and BC are legs of the right angled triangle ABC.

Side AB lies on the y-axis because the x-coordinate of both A and B is 0.

Two legs are perpendicular to each other. So, BC must be parallel to x-axis and the y-coordinate of both B and C is must be same.

4a-5=2a+6

4a-2a=5+6

2a=11

Divide both sides by 2.

a=\frac{11}{2}

The value of a is 2. So the coordinates of triangle ABC are

B(0,4a-5)=B(0,4(\frac{11}{2})-5)\Rightarrow B(0,17)

C(2a+1,2a+6)=C(2(\frac{11}{2})+1,2(\frac{11}{2})+6)\Rightarrow C(12,17)

The area of a triangle is

Area=\frac{1}{2}|x_1(y_2-y_3)+x_2(y_3-y_1)+x_3(y_1-y_2)|

The area of triangle ABC is

Area=\frac{1}{2}|0(17-17)+0(17-0)+12(0-17)|

Area=\frac{1}{2}|12(-17)|

Area=\frac{1}{2}|-204|

Area=\frac{1}{2}(204)

Area=102

The area of triangle ABC is 102. Therefore the correct option is 1.

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