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Digiron [165]
3 years ago
7

Given the function h(x) = 4^x, Section A is from x = 0 to x = 1 and Section B is from x = 2 to x = 3.

Mathematics
1 answer:
Aleksandr [31]3 years ago
5 0
A)  average rate=Δy/Δx=(y2-y1)/(x2-x1)=(h2-h1)/(x2-x1)
from x1 = 0 to x2= 1, <span>h(x) = 4^x, h(0)=4^0=1, h(1)=4^1=4
</span>average rate=(h2-h1)/(x2-x1)=(4-1)/(1-0)=3  (section A for interval x=0 to x=1)
from x1 = 2 to x2= 3, h(x) = 4^x, h(0)=4^2=16, h(1)=4^3=64
average rate=(h2-h1)/(x2-x1)=(64-16)/(3-2)=48  (section B for interval x=2 to x=3)
B) av.rate section B/ av. rate section A=48/4=12
this is exponential function, and for Δx=1, Δy change more  for bigger numbers

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6x + 7 = 13 + 7x pls solve this for me
AURORKA [14]

Answer:

Isolate the variable by dividing each side by factors that don't contain the variable.   x=−6

6*-6 + 7 = 13 + 7*-6

  -29     =     -29

Step-by-step explanation:

there is your answer for you

im sorry if wrong

4 0
2 years ago
Read 2 more answers
Part A: The club has learned from experience over the years that when they do not charge an admission fee, attendance is 800 peo
sesenic [268]

Answer:

750

Step-by-step explanation:

800 - 8p = 750

5 0
3 years ago
Find an​ nth-degree polynomial function with real coefficients satisfying the given conditions calulator?
fgiga [73]

Answer:

Degree = 4

Step-by-step explanation:

For the given conditions:

n = 4

i and 5i are zeros

f(-2) = 145

For zeros, it means they are a quadratic factor of the expression

It means, we will have x = ± i and x = ± 5i

therefore, the given factors are (x - i)(x + i)(x - 5i)(x + 5i)

Hence, we have the function

given degree = 4

f(x) = a(x-i)(x+i)(x-5i)(x+5i)

f(x) = a(x² + 1)(x² + 25)

Hence, substituting -2 for x, we have

f(-2) = a(5)(29) = 145

Hence, a = 1

f(x) = x⁴ + 26x² + 25

Therefore, we can see that the given degree = 4

3 0
3 years ago
Please help asap 18 pts + brainliest to right/best answer
saul85 [17]

Which two numbers add up to -29 and multiply to 100?

-25 and -4

Rewrite the expression

<u>(x - 25)(x - 4)</u>

7 0
3 years ago
What is the sum of the roots of the polynomial shown below?<br> f(x) = x^3 + 2x^2 - 11x-12
svp [43]

<u>Answer:  </u>

Sum of the roots of the polynomial x^{3}+2 x^{2}-11 x-12 \text { is }-2

<u>Solution:</u>

The general form of cubic polynomial is a x^{3}+b x^{2}+c x+d=0 ---- (1)

If we have any cubic polynomial a x^{3}+b x^{2}+c x+d=0 having roots \alpha , \beta , \theta

Sum of roots \alpha + \beta + \theta = \frac{-b}{a} ---(2)

From question given that,

x^{3}+2 x^{2}-11 x-12 --- (3)

On comparing equation (1) and (3), we get a = 1, b = 2, c = -11 and d = -12

Hence the sum of roots using eqn 2 is given as,

= \frac{-2}{1}

= -2

Hence the sum of the roots of the polynomial x^{3}+2 x^{2}-11 x-12 \text { is }-2

4 0
3 years ago
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