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Digiron [165]
3 years ago
7

Given the function h(x) = 4^x, Section A is from x = 0 to x = 1 and Section B is from x = 2 to x = 3.

Mathematics
1 answer:
Aleksandr [31]3 years ago
5 0
A)  average rate=Δy/Δx=(y2-y1)/(x2-x1)=(h2-h1)/(x2-x1)
from x1 = 0 to x2= 1, <span>h(x) = 4^x, h(0)=4^0=1, h(1)=4^1=4
</span>average rate=(h2-h1)/(x2-x1)=(4-1)/(1-0)=3  (section A for interval x=0 to x=1)
from x1 = 2 to x2= 3, h(x) = 4^x, h(0)=4^2=16, h(1)=4^3=64
average rate=(h2-h1)/(x2-x1)=(64-16)/(3-2)=48  (section B for interval x=2 to x=3)
B) av.rate section B/ av. rate section A=48/4=12
this is exponential function, and for Δx=1, Δy change more  for bigger numbers

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Step-by-step explanation:

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He paid monthly payments of $252.34 for 4 years. Which mean $252.34 is paid for 48 months, multiplication $252.34 and 48 are $12,112.32. So we have monthly payments is $12,112.32

The total amount Tony ended up for the car is $11,400 + $12,112.32 = $24,512.32

b. The interest Tony pay on the loan is $12,112.32 - $11,400 = $712.32

3 0
3 years ago
Which shows one way to determine the factors of x^3 - 9x^2 + 5x - 45 by grouping ?
adoni [48]
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(x^3-9x^2)+(5x-45)=x^2(x-9)+5(x-9)=(x-9)(x^2+5).
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It will be smaller than one

Step-by-step explanation:

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7 0
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7 0
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