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SpyIntel [72]
3 years ago
11

Use the​ power-reducing formulas to rewrite the expression as an equivalent expression that does not contain powers of trigonome

tric functions greater than 1. 40sin^2xcos^2x
Mathematics
2 answers:
ratelena [41]3 years ago
7 0

Answer:

x = 0.175\cdot (1-\cos 4\cdot \theta)

Step-by-step explanation:

Let use the following trigonometric identities:

\sin^{2}\theta = \frac{1-\cos 2\cdot \theta}{2} \\\cos^{2}\theta = \frac{1+\cos 2\cdot \theta}{2}

Then, the equation is simplified by substituting its components:

x = 1.40\cdot \left(\frac{1-\cos 2\cdot \theta}{2}  \right)\cdot \left(\frac{1+\cos 2\cdot \theta}{2} \right)

x = 0.35\cdot (1-\cos^{2}2\cdot \theta)

x = 0.35\cdot \sin^{2}2\cdot \theta

x = 0.35\cdot \left(\frac{1-\cos 4\cdot \theta}{2}  \right)

x = 0.175\cdot (1-\cos 4\cdot \theta)

zalisa [80]3 years ago
4 0

Answer:

(1/8) - (1/8)* [cos (4x)]

Step-by-step explanation:

We will apply the corresponding formulas and through algebra we will reach the result in the following steps:

Sin^2 (x) * Cos^2 (x) = {[1 - cos (2x)]/2}*{[1 + cos (2x)]/2}

Sin^2 (x) * Cos^2 (x) =[ 1 - cos^2 (2x)]/4

Sin^2 (x) * Cos^2 (x) = (1/4) - (1/4) * cos^2 (2x)

Sin^2 (x) * Cos^2 (x) =  (1/4) - (1/4) * {[1 + cos (2*2x)]/2}

Sin^2 (x) * Cos^2 (x) =  (1/4) - (1/8) * [1 + cos (4x)]

Sin^2 (x) * Cos^2 (x) =  (1/4) - (1/8) - (1/8)* [cos (4x)]

Sin^2 (x) * Cos^2 (x) =  (1/8) - (1/8)* [cos (4x)]

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