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sergey [27]
2 years ago
11

Noise in a quiet room is 500 times as intense as the threshold of sound. What is the decibel measurement for the quiet room? 20

decibels 28 decibels 200 decibels 280 decibels.
Mathematics
1 answer:
netineya [11]2 years ago
7 0

The intensity and the threshold of the noise are illustrations of rates

The decibel measurement of a quiet room is 28

<h3>How to determine the decibel measurement</h3>

From the graph that completes the question, we have the following point

(Decibel, Intense) = (28,500)

This means that, the decibel measurement is 28

Hence, the decibel measurement of a quiet room is 28

Read more about sound and noise at:

brainly.com/question/13741664

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Answer:

Step-by-step explanation:

You don't need the Law of Cosines, the Law of sines if what you need. You can't use the Law of Cosines because in order to find side a, you would need the length of side c and you don't have it. Using the Law of Sines is appropriate, knowing that angle B = 55:

\frac{sin55}{175}=\frac{sin42}{a} and solving for a:

a=\frac{175sin42}{sin55} so

a = 143.0

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pioneers are buying mules to trek across the country. each of the 5 wagons require e mules to pull them. write the equation to e
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Answer:

d = 5e

Step-by-step explanation:

Number of wagons = 5

Number of miles per wagon = e

Total number of mules = d

Hence, relationship between total mules d needed will be ;

Total mules = number of wagons * Numbe rof mules per wagon

d = 5e

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Evaluate the expression for the given value of each variable.
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Is this a function,why or why not
andre [41]

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Read 2 more answers
For every integer k from 1 to 10, inclusive the "k"th term of a certain sequence is given by (−1)(k+1)∗(12k). If T is the sum of
Katena32 [7]

Answer:

Option D. is the correct option.

Step-by-step explanation:

In this question expression that represents the kth term of a certain sequence is not written properly.

The expression is (-1)^{k+1}(\frac{1}{2^{k}}).

We have to find the sum of first 10 terms of the infinite sequence represented by the expression given as (-1)^{k+1}(\frac{1}{2^{k}}).

where k is from 1 to 10.

By the given expression sequence will be \frac{1}{2},\frac{(-1)}{4},\frac{1}{8}.......

In this sequence first term "a" = \frac{1}{2}

and common ratio in each successive term to the previous term is 'r' = \frac{\frac{(-1)}{4}}{\frac{1}{2} }

r = -\frac{1}{2}

Since the sequence is infinite and the formula to calculate the sum is represented by

S=\frac{a}{1-r} [Here r is less than 1]

S=\frac{\frac{1}{2} }{1+\frac{1}{2}}

S=\frac{\frac{1}{2}}{\frac{3}{2} }

S = \frac{1}{3}

Now we are sure that the sum of infinite terms is \frac{1}{3}.

Therefore, sum of 10 terms will not exceed \frac{1}{3}

Now sum of first two terms = \frac{1}{2}-\frac{1}{4}=\frac{1}{4}

Now we are sure that sum of first 10 terms lie between \frac{1}{4} and \frac{1}{3}

Since \frac{1}{2}>\frac{1}{3}

Therefore, Sum of first 10 terms will lie between \frac{1}{4} and \frac{1}{2}.

Option D will be the answer.

3 0
3 years ago
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