Answer:
<u><em>14 pounds of strawberries and 42 pounds of peaches are sold</em></u>
Step-by-step explanation:
Suppose the pounds of strawberries sold are x and pounds of peaches sold are y. then
$182= x(1) + y(4)--------A
or 182= x(1) +3x(4)------- B
182=x+12x
182/13=x
x=14
I am pretty sure it is 0.064. Hope this helps
Answer:Option A is correct.
y-2=0
Step-by-step explanation:
Option A is correct.
General form of the equation of the line: y-2 = 0
Step-by-step explanation:
The general form of the equation is given by:
y = mx +b where m is the slope and b is the y-intercept.
y-intercepts of the line is the value of y at the point where the line crosses the y-axis(i.e x= 0)
From the given figure;
we can see that the line crosses the y-axis at y =2 and also here the slope is , m= 0
therefore, by definition of y-intercepts
y-intercept (b) = 2
Therefore, the equation of line as shoen in figure is:
y = (0)x + 2
or
y = 2
y-2 = 0
Therefore, the general form of the equation line as shown in the figure is:
y-2 =0
Sunscreen approx. 40.6 cents an oz
Lotion 6.4 cents an oz
Answer:
ans=13.59%
Step-by-step explanation:
The 68-95-99.7 rule states that, when X is an observation from a random bell-shaped (normally distributed) value with mean 
and standard deviation 
, we have these following probabilities
In our problem, we have that:
The distribution of the number of months in service for the fleet of cars is bell-shaped and has a mean of 53 months and a standard deviation of 11 months
So 
So:
-----------
-----
What is the approximate percentage of cars that remain in service between 64 and 75 months?
Between 64 and 75 minutes is between one and two standard deviations above the mean.
We have 
subtracted by is the percentage of cars that remain in service between one and two standard deviation, both above and below the mean.
To find just the percentage above the mean, we divide this value by 2
So:
The approximate percentage of cars that remain in service between 64 and 75 months is 13.59%.
